A333210 Variation of Van Eck's sequence A181391: a(n+1) = the minimum positive offset m from a(n) such that a(n-m-1)+a(n-m) = a(n-1)+a(n); a(n+1)=0 if no such m exists. Start with a(1) = a(2) = 0.
0, 0, 0, 1, 0, 1, 1, 0, 2, 2, 0, 2, 1, 0, 6, 0, 1, 3, 8, 0, 0, 18, 0, 1, 7, 5, 0, 0, 7, 0, 1, 7, 7, 0, 4, 17, 0, 0, 10, 0, 1, 10, 23, 0, 0, 7, 12, 0, 22, 0, 1, 10, 10, 0, 14, 22, 0, 7, 12, 12, 0, 13, 0, 1, 13, 10, 22, 0, 11, 17, 0, 34, 0, 1, 10, 6, 0, 61, 0, 1, 6, 23, 0, 17, 13, 0, 23, 4, 0, 54, 0, 1, 12
Offset: 1
Keywords
Examples
a(3) = 0 as a(1)+a(2) = 0+0 = 0, which has not previously appeared as the sum of two adjacent terms. a(4) = 1 as a(2)+a(3) = 0+0 = 0, which equals the sum a(1)+a(2), one term back from a(3). a(5) = 0 as a(3)+a(4) = 0+1 = 1, which has not previously appeared as the sum of two adjacent terms. a(6) = 1 as a(4)+a(5) = 1+0 = 1, which equals the sum a(3)+a(4), one term back from a(5). a(19) = 8 as a(17)+a(18) = 1+3 = 4, which equals the sum a(9)+a(10), eight terms back from a(18).
Links
- Scott R. Shannon, Table of n, a(n) for n = 1..10000.
- Brady Haran and N. J. A. Sloane, Don't Know (the Van Eck Sequence), Numberphile video (2019).
Comments