A318259 Generalized Worpitzky numbers W_{m}(n,k) for m = 2, n >= 0 and 0 <= k <= n, triangle read by rows.
1, -1, 1, 5, -11, 6, -61, 211, -240, 90, 1385, -6551, 11466, -8820, 2520, -50521, 303271, -719580, 844830, -491400, 113400, 2702765, -19665491, 58998126, -93511440, 82661040, -38669400, 7484400, -199360981, 1704396331, -6187282920, 12372329970, -14727913200, 10443232800, -4086482400, 681080400
Offset: 0
Examples
[0] [ 1] [1] [ -1, 1] [2] [ 5, -11, 6] [3] [ -61, 211, -240, 90] [4] [ 1385, -6551, 11466, -8820, 2520] [5] [ -50521, 303271, -719580, 844830, -491400, 113400] [6] [2702765, -19665491, 58998126, -93511440, 82661040, -38669400, 7484400]
Links
- Matthieu Josuat-Vergès and Jang Soo Kim, Touchard-Riordan formulas, T-fractions, and Jacobi's triple product identity, arXiv:1101.5608 [math.CO], 2011.
Crossrefs
Programs
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Maple
Joffe := proc(n, k) option remember; if k > n then 0 elif k = 0 then k^n else k*(2*k-1)*Joffe(n-1, k-1)+k^2*Joffe(n-1, k) fi end: T := (n, k) -> add((-1)^(k-j)*binomial(n-j, n-k)*add((-1)^i*Joffe(n,i)* binomial(n-i, j), i=0..n), j=0..k): seq(seq(T(n, k), k=0..n), n=0..6);
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Mathematica
Joffe[0, 0] = 1; Joffe[n_, k_] := Joffe[n, k] = If[k>n, 0, If[k == 0,k^n, k*(2*k-1)*Joffe[n-1, k-1] + k^2*Joffe[n-1, k]]]; T[n_, k_] := Sum[(-1)^(k-j)*Binomial[n-j, n-k]*Sum[(-1)^i*Joffe[n, i]* Binomial[n-i, j], {i, 0, n}], {j, 0, k}]; Table[T[n, k], {n, 0, 7}, {k, 0, n}] // Flatten (* Jean-François Alcover, Feb 18 2019, from Maple *)
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Sage
def EW(m, n): @cached_function def S(m, n): R.
= ZZ[] if n == 0: return R(1) return R(sum(binomial(m*n, m*k)*S(m, n-k)*x for k in (1..n))) s = S(m, n).list() c = lambda k: sum((-1)^(k-j)*binomial(n-j,n-k)* sum((-1)^i*s[i]*binomial(n-i,j) for i in (0..n)) for j in (0..k)) return [c(k) for k in (0..n)] def A318259row(n): return EW(2, n) flatten([A318259row(n) for n in (0..6)])
Formula
Let S(n, k) denote Joffe's central differences of zero (A241171) extended to the case n = 0 and k = 0 by prepending a column 1, 0, 0, 0,... to the triangle, then:
T(n,k) = Sum_{j=0..k}((-1)^(k-j)*C(n-j,n-k)*Sum_{i=0..n}((-1)^i*S(n,i)*C(n-i,j))).
Comments