A319445 Number of Eisenstein integers in a reduced system modulo n.

1, 3, 6, 12, 24, 18, 36, 48, 54, 72, 120, 72, 144, 108, 144, 192, 288, 162, 324, 288, 216, 360, 528, 288, 600, 432, 486, 432, 840, 432, 900, 768, 720, 864, 864, 648, 1296, 972, 864, 1152, 1680, 648, 1764, 1440, 1296, 1584, 2208, 1152, 1764, 1800, 1728, 1728, 2808

Offset: 1

Author

Jianing Song, Sep 19 2018

Keywords

• nonn
• mult

Comments

Equivalent of phi (A000010) in the ring of Eisenstein integers.

Number of units in the ring Z[w]/nZ[w], where Z[w] is the ring of Eisenstein integers.

a(n) is the number of elements in G(n) = {a + b*w: a, b in Z/nZ and gcd(a^2 + a*b + b^2, n) = 1} where w = (1 + sqrt(3)*i)/2.

a(n) is the number of ordered pairs (a, b) modulo n such that gcd(a^2 + a*b + b^2, n) = 1.

For n > 2, a(n) is divisible by 6.

Examples

			Let w = (1 + sqrt(3)*i)/2, w' = (1 - sqrt(3)*i)/2.
{1, w, w'} is the set of 3 units in the Eisenstein integers modulo 2, so a(2) = 3.
{1, w, w^2, -1, w', w'^2} is the set of 6 units in the Eisenstein integers modulo 3, so a(3) = 6.
{1, w, w'} is the set of 3 units in the Eisenstein integers modulo 2, so a(2) = 3.
{1, w, 1 + w, w', 1 + w', -1 + 2w, -1, -w, -1 - w, -w', -1 - w', -1 + 2w'} is the set of 12 units in the Eisenstein integers modulo 4, so a(4) = 12.
		

Links

• Jianing Song, Table of n, a(n) for n = 1..10000
• Wikipedia, Eisenstein integer

Crossrefs

Cf. A007434.

Equivalent of arithmetic functions in the ring of Eisenstein integers (the corresponding functions in the ring of integers are in the parentheses): A319442 ("d", A000005), A319449 ("sigma", A000203), this sequence ("phi", A000010), A319446 ("psi", A002322), A319443 ("omega", A001221), A319444 ("Omega", A001222), A319448 ("mu", A008683).

Equivalent in the ring of Gaussian integers: A079458.

Programs

Mathematica

f[p_, e_] := If[p == 3 , 2*3^(2*e - 1), Switch[Mod[p, 3], 1, (p - 1)^2*p^(2*e - 2), 2, (p^2 - 1)*p^(2*e - 2)]]; eisPhi[1] = 1; eisPhi[n_] := Times @@ f @@@ FactorInteger[n]; Array[eisPhi, 100] (* Amiram Eldar, Feb 10 2020 *)

PARI

a(n)=
{
    my(r=1, f=factor(n));
    for(j=1, #f[, 1], my(p=f[j, 1], e=f[j, 2]);
        if(p==3, r*=2*3^(2*e-1));
        if(p%3==1, r*=(p-1)^2*p^(2*e-2));
        if(p%3==2, r*=(p^2-1)*p^(2*e-2));
    );
    return(r);
}

Formula

Multiplicative with a(3^e) = 2*3^(2*e-1), a(p^e) = phi(p^e)^2 = (p-1)^2*p^(2*e-2) if p == 1 (mod 3) and J_2(p^e) = A007434(p^e) = (p^2 - 1)*p^(2*e-2) if p == 2 (mod 3).

Sum_{k=1..n} a(k) ~ c * n^3, where c = (8/27) * Product_{p prime == 1 (mod 3)} (1 - 2/p^2 + 1/p^3) * Product_{p prime == 2 (mod 3)} (1 - 1/p^3) = 0.2410535987... . - Amiram Eldar, Feb 13 2024