A343963 a(0) = 0, and for any n > 0, the binary expansion of n has n digits and starts with the binary expansion of n, say of w digits, and in case n > w, the remaining binary digits in a(n) are those of a(n-w).
0, 1, 2, 7, 9, 22, 55, 121, 137, 310, 695, 1529, 3209, 6966, 15031, 32249, 34297, 72841, 154422, 326327, 687609, 1410553, 2956425, 6183734, 12909239, 26902009, 55936505, 116202633, 241064758, 499448503, 1033534969, 2136311289, 2203420153, 4545387657
Offset: 0
Examples
For n = 10: - the binary expansion of a(10) has 10 digits, and is the concatenation of: - the binary expansion of 10 which is "1010", - the binary expansion of 10 - 4 = 6 which is "110", - the binary expansion of 10 - 4 - 3 = 3 which is "11", - the binary expansion of 10 - 4 - 3 - 2 = 1 which is "1", - as 10 = 4 + 3 + 2 + 1, we stop here, - so the binary expansion of a(10) is "1010110111", - and a(10) = 695.
Links
- Rémy Sigrist, Binary plot of the sequence for n <= 2^10
Programs
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PARI
a(n) = { if (n==0, 0, my (k=n-#binary(n)); n*2^k+a(k)) }
Formula
A070939(a(n)) = n for any n > 0.
Comments