A322034 - cp's OEIS frontend

A322034 Let p1 <= p2 <= ... <= pk be the prime factors of n, with repetition; let s = 1/p1 + 1/(p1p2) + 1/(p1p2p3) + ... + 1/(p1p2...pk); a(n) = numerator of s. a(1)=0 by convention.

n	a(n)
1	0
2	1
3	1
4	3
5	1
6	2
7	1
8	7
9	4
10	3
11	1
12	5
13	1
14	4
15	2
16	15
17	1
18	13
19	1
20	4
21	8
22	6
23	1
24	11
25	6
26	7
27	13
28	11
29	1
30	7
31	1
32	31
33	4
34	9
35	8
36	31
37	1
38	10
39	14
40	9
41	1
42	29
43	1
44	17
45	7
46	12
47	1
48	23
49	8
50	31
51	6
52	10
53	1
54	20
55	12
56	25
57	20
58	15
59	1
60	17
61	1
62	16
63	29
64	63
65	14
66	15
67	1
68	13
69	8
70	43
71	1
72	67

[0, 1, 1, 3, 1, 2, 1, 7, 4, 3, 1, 5, 1, 4, 2, 15, 1, 13, 1, 4, 8, 6, 1, 11, 6, 7, 13, 11, 1, 7, 1, 31, 4, 9, 8, 31, 1, 10, 14, 9, 1, 29, 1, 17, 7, 12, 1, 23, 8, 31, 6, 10, 1, 20, 12, 25, 20, 15, 1, 17, 1, 16, 29, 63, 14, 15, 1, 13, 8, 43, 1, 67]

cp's OEIS Frontend

A322034 Let p1 <= p2 <= ... <= pk be the prime factors of n, with repetition; let s = 1/p1 + 1/(p1p2) + 1/(p1p2p3) + ... + 1/(p1p2...pk); a(n) = numerator of s. a(1)=0 by convention.

Table of values

List of values

n	a(n)
1	0
2	1
3	1
4	3
5	1
6	2
7	1
8	7
9	4
10	3
11	1
12	5
13	1
14	4
15	2
16	15
17	1
18	13
19	1
20	4
21	8
22	6
23	1
24	11
25	6
26	7
27	13
28	11
29	1
30	7
31	1
32	31
33	4
34	9
35	8
36	31
37	1
38	10
39	14
40	9
41	1
42	29
43	1
44	17
45	7
46	12
47	1
48	23
49	8
50	31
51	6
52	10
53	1
54	20
55	12
56	25
57	20
58	15
59	1
60	17
61	1
62	16
63	29
64	63
65	14
66	15
67	1
68	13
69	8
70	43
71	1
72	67

n	a(n)
1	0
2	1
3	1
4	3
5	1
6	2
7	1
8	7
9	4
10	3
11	1
12	5
13	1
14	4
15	2
16	15
17	1
18	13
19	1
20	4
21	8
22	6
23	1
24	11
25	6
26	7
27	13
28	11
29	1
30	7
31	1
32	31
33	4
34	9
35	8
36	31
37	1
38	10
39	14
40	9
41	1
42	29
43	1
44	17
45	7
46	12
47	1
48	23
49	8
50	31
51	6
52	10
53	1
54	20
55	12
56	25
57	20
58	15
59	1
60	17
61	1
62	16
63	29
64	63
65	14
66	15
67	1
68	13
69	8
70	43
71	1
72	67

cp's OEIS Frontend

A322034 Let p1 <= p2 <= ... <= pk be the prime factors of n, with repetition; let s = 1/p1 + 1/(p1*p2) + 1/(p1*p2*p3) + ... + 1/(p1*p2*...*pk); a(n) = numerator of s. a(1)=0 by convention.

Table of values

List of values

A322034 Let p1 <= p2 <= ... <= pk be the prime factors of n, with repetition; let s = 1/p1 + 1/(p1p2) + 1/(p1p2p3) + ... + 1/(p1p2...pk); a(n) = numerator of s. a(1)=0 by convention.

n	a(n)
1	0
2	1
3	1
4	3
5	1
6	2
7	1
8	7
9	4
10	3
11	1
12	5
13	1
14	4
15	2
16	15
17	1
18	13
19	1
20	4
21	8
22	6
23	1
24	11
25	6
26	7
27	13
28	11
29	1
30	7
31	1
32	31
33	4
34	9
35	8
36	31
37	1
38	10
39	14
40	9
41	1
42	29
43	1
44	17
45	7
46	12
47	1
48	23
49	8
50	31
51	6
52	10
53	1
54	20
55	12
56	25
57	20
58	15
59	1
60	17
61	1
62	16
63	29
64	63
65	14
66	15
67	1
68	13
69	8
70	43
71	1
72	67