cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A324592 Square array T(n, k) read by diagonals, n > 0, k > 0; for any number m > 0 with prime factorization Product_{i > 0} prime(i)^e(i), let f(m) = Sum_{i > 0} e(i) * sqrt(A005117(i)); f establishes a bijection between the positive numbers and the finite sums of square roots of squarefree numbers; let g be the inverse of f; T(n, k) = g(f(n) * f(k)).

Original entry on oeis.org

1, 1, 1, 1, 2, 1, 1, 3, 3, 1, 1, 4, 4, 4, 1, 1, 5, 9, 9, 5, 1, 1, 6, 11, 16, 11, 6, 1, 1, 7, 12, 25, 25, 12, 7, 1, 1, 8, 17, 36, 8, 36, 17, 8, 1, 1, 9, 27, 49, 55, 55, 49, 27, 9, 1, 1, 10, 16, 64, 31, 72, 31, 64, 16, 10, 1, 1, 11, 33, 81, 125, 119, 119, 125
Offset: 1

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Author

Rémy Sigrist, Sep 03 2019

Keywords

Comments

The set of square roots of squarefree numbers, { sqrt(A005117(i)), i > 0 }, is Q-linearly independent. The set of finite sums of square roots of squarefree numbers is closed under multiplication, hence the sequence is well defined.
The function f can be naturally extended to the set of positive rational numbers: if r = u/v (not necessarily in reduced form), then f(r) = f(u) - f(v).
This sequence has similarities with A297845.

Examples

			Array T(n, k) begins:
  n\k|  1   2   3    4    5    6    7     8     9    10
  ---+-------------------------------------------------
    1|  1   1   1    1    1    1    1     1     1     1
    2|  1   2   3    4    5    6    7     8     9    10
    3|  1   3   4    9   11   12   17    27    16    33
    4|  1   4   9   16   25   36   49    64    81   100
    5|  1   5  11   25    8   55   31   125   121    40
    6|  1   6  12   36   55   72  119   216   144   330
    7|  1   7  17   49   31  119   32   343   289   217
    8|  1   8  27   64  125  216  343   512   729  1000
    9|  1   9  16   81  121  144  289   729   256  1089
   10|  1  10  33  100   40  330  217  1000  1089   400
For n = 3 and k = 5:
- f(3) = f(prime(2)) = sqrt(A005117(2)) = sqrt(2),
- f(5) = f(prime(3)) = sqrt(A005117(3)) = sqrt(3),
- f(3) * f(5) = sqrt(6) = sqrt(A005117(5)),
- hence T(3, 5) = prime(5) = 11.
		

Crossrefs

Programs

  • PARI
    See Links section.

Formula

For any m > 0, n > 0 and k > 0:
- T(n, k) = T(k, n) (T is commutative),
- T(m, T(n, k)) = T(T(m, n), k) (T is associative),
- T(m, n*k) = T(m, n) * T(m, k) and T(n*k, m) = T(n, m) * T(k, m) (T is completely multiplicative in both parameters),
- T(n, 1) = 1 (1 is an absorbing element for T),
- T(n, 2) = n (2 is an identity element for T),
- T(n, 2^i) = n^i for any i >= 0,
- A001221(T(n, k)) <= A001221(n) * A001221(k),
- T(prime(n), prime(n)) = 2^A005117(n) (where prime(n) denotes the n-th prime number).