A327225 For any n >= 0, let u and v be such that 2 <= u < v and the digits of n in bases u and v are the same up to a permutation and v is minimized; a(n) = u.
2, 2, 3, 4, 5, 6, 7, 3, 9, 4, 11, 5, 13, 4, 15, 7, 5, 5, 19, 6, 21, 5, 3, 7, 25, 6, 6, 13, 4, 9, 7, 7, 33, 8, 8, 11, 7, 7, 7, 19, 13, 13, 10, 10, 7, 7, 5, 9, 49, 9, 8, 5, 4, 10, 13, 13, 9, 9, 9, 19, 61, 10, 10, 10, 9, 9, 5, 9, 6, 13, 11, 11, 73, 10, 9, 12, 9
Offset: 0
Examples
For n = 11: - the representations of 11 in bases b = 2..9 are: b 11 in base b - ------------ 2 "1011" 3 "102" 4 "23" 5 "21" 6 "15" 7 "14" 8 "13" 9 "12" - the representation in base 9 is the least that shows the same digits, up to order, to some former base, namely the base 5, - hence a(11) = 5.
Links
- Rémy Sigrist, Table of n, a(n) for n = 0..10000
Programs
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PARI
a(n) = { my (s=[]); for (v=2, oo, my (d=vecsort(digits(n,v))); if (setsearch(s,d), forstep (u=v-1, 2, -1, if (vecsort(digits(n,u))==d, return (u))), s=setunion(s,[d]))) }
Formula
a(n) <= max(2, n+1).
Comments