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A327846 Full days remaining in the month on the Gregorian calendar starting at n-th day of a non-leap year.

%I A327846 #20 Mar 08 2020 23:25:54
%S A327846 30,29,28,27,26,25,24,23,22,21,20,19,18,17,16,15,14,13,12,11,10,9,8,7,
%T A327846 6,5,4,3,2,1,0,27,26,25,24,23,22,21,20,19,18,17,16,15,14,13,12,11,10,
%U A327846 9,8,7,6,5,4,3,2,1,0,30,29,28,27,26,25,24,23,22,21,20,19,18,17,16,15,14,13,12,11,10,9,8,7,6
%N A327846 Full days remaining in the month on the Gregorian calendar starting at n-th day of a non-leap year.
%H A327846 Jinyuan Wang, <a href="/A327846/b327846.txt">Table of n, a(n) for n = 1..365</a>
%e A327846 On March 27th, the 86th day of the year where n=86, there are 4 full days left in the month of March, a(86)=4.
%t A327846 Array[Range[# - 1, 0, -1] &@ Which[MemberQ[{4, 6, 9, 11}, #], 30, # == 2, 28, True, 31] &, 12] // Flatten (* _Michael De Vlieger_, Sep 30 2019 *)
%o A327846 (C++)
%o A327846 #include <iostream>
%o A327846 using namespace std;
%o A327846 int main(){
%o A327846     int m=1;
%o A327846     for(int d=30;m<=12;d--){
%o A327846         cout<<d<<",";
%o A327846         if(d==0){
%o A327846             m++;
%o A327846             if(m==4||m==6||m==9||m==11)
%o A327846                 d=30;
%o A327846             else if(m==2)
%o A327846                 d=28;
%o A327846             else
%o A327846                 d=31;
%o A327846         }
%o A327846     }
%o A327846 }
%Y A327846 Cf. A061251, A073304.
%K A327846 nonn,fini,full
%O A327846 1,1
%A A327846 _Andrew Pham_, Sep 27 2019