cp's OEIS Frontend

A328236 The least m > 1 such that the arithmetic derivative of m*n is a multiple of the arithmetic derivative of n.

%I A328236 #10 Oct 10 2019 20:32:28
%S A328236 2,2,2,2,6,2,8,4,10,2,4,2,14,12,4,2,10,2,8,21,22,2,24,4,26,2,12,2,30,
%T A328236 2,6,33,34,8,6,2,18,12,40,2,42,2,8,22,46,2,10,4,14,32,33,2,8,12,56,24,
%U A328236 30,2,56,2,62,40,8,65,66,2,65,69,70,2,22,2,45,24,32,65,78,2,24,4,82,2,30,24,50,16,88,2,42,32,20,40
%N A328236 The least m > 1 such that the arithmetic derivative of m*n is a multiple of the arithmetic derivative of n.
%H A328236 Antti Karttunen, <a href="/A328236/b328236.txt">Table of n, a(n) for n = 2..16385</a>
%H A328236 Antti Karttunen, <a href="/A328236/a328236.txt">Data supplement: n, a(n) computed for n = 2..65537</a>
%e A328236 Arithmetic derivative of 6 is 6' = A003415(6) = 5. Taking arithmetic derivatives of successive multiples of six we obtain 12' = 16, 18' = 21, 24' = 44, 30' = 31, and not until with A003415(6*6) = 36' = 60 we obtain a multiple of 5. Thus a(6) = 6.
%o A328236 (PARI)
%o A328236 A003415(n) = if(n<=1, 0, my(f=factor(n)); n*sum(i=1, #f~, f[i, 2]/f[i, 1]));
%o A328236 A328236(n) = { my(d=A003415(n)); for(m=2,oo,if(!(A003415(n*m)%d), return(m))); };
%Y A328236 Cf. A003415, A328235, A328238 (gives the corresponding quotients).
%K A328236 nonn
%O A328236 2,1
%A A328236 _Antti Karttunen_, Oct 08 2019