A329512 Array read by upward antidiagonals: row n = coordination sequence for cylinder formed by rolling up a strip of width 2*n hexagons cut from the hexagonal grid by cuts perpendicular to grid lines.
1, 1, 3, 1, 3, 4, 1, 3, 6, 4, 1, 3, 6, 9, 4, 1, 3, 6, 9, 9, 4, 1, 3, 6, 9, 12, 8, 4, 1, 3, 6, 9, 12, 15, 8, 4, 1, 3, 6, 9, 12, 15, 14, 8, 4, 1, 3, 6, 9, 12, 15, 18, 12, 8, 4, 1, 3, 6, 9, 12, 15, 18, 21, 12, 8, 4
Offset: 1
Examples
Array begins: 1, 3, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, ... 1, 3, 6, 9, 9, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, ... 1, 3, 6, 9, 12, 15, 14, 12, 12, 12, 12, 12, 12, 12, 12, 12, 12, 12, 12, 12, ... 1, 3, 6, 9, 12, 15, 18, 21, 19, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, ... 1, 3, 6, 9, 12, 15, 18, 21, 24, 27, 24, 20, 20, 20, 20, 20, 20, 20, 20, 20, ... 1, 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 29, 24, 24, 24, 24, 24, 24, 24, ... 1, 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 34, 28, 28, 28, 28, 28, ... 1, 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 39, 32, 32, 32, ... 1, 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 44, 36, 36, ... ... The initial antidiagonals are: 1, 1, 3, 1, 3, 4, 1, 3, 6, 4, 1, 3, 6, 9, 4, 1, 3, 6, 9, 9, 4, 1, 3, 6, 9, 12, 8, 4, 1, 3, 6, 9, 12, 15, 8, 4, 1, 3, 6, 9, 12, 15, 14, 8, 4, 1, 3, 6, 9, 12, 15, 18, 12, 8, 4, ...
Links
- Chaim Goodman-Strauss and N. J. A. Sloane, A Coloring Book Approach to Finding Coordination Sequences, Acta Cryst. A75 (2019), 121-134, also on NJAS's home page. Also arXiv:1803.08530.
- N. J. A. Sloane, Illustration for row n = 1, showing vertices of cylinder of width (or circumference) 2 labeled with distance from base point 0. The cylinder is formed by identifying the black lines. Arrows indicate two points which will coalesce.
- N. J. A. Sloane, Illustration for row n = 2, showing vertices of cylinder of width (or circumference) 4 labeled with distance from base point 0. The cylinder is formed by identifying the black lines. Arrows indicate two points which will coalesce.
- Index entries for coordination sequences
Programs
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Magma
n := 2; \\ set n R
:= RationalFunctionField(Integers()); FG3 := FreeGroup(3); Q3 := quo ; H := AutomaticGroup(Q3); f3 := GrowthFunction(H); PSR := PowerSeriesRing(Integers():Precision := 60); Coefficients(PSR!f3); // 1, 3, 6, 9, 12, 15, 14, 12, 12, 12, 12, 12, 12, 12, 12, ... (row n) f3; // G(n) // (x^3-2*x^2-1)*(1+x)^2/(x-1)
Formula
The g.f.s for the rows could be found using the "trunks and branches" method (see Goodman-Strauss and Sloane), as was done in A329508. This step has not yet been carried out, so the following g.f. is at present only conjectural.
The g.f. G(n) for row n (n>=1) is (strongly) conjectured to be
(1/(1-x))*(1 + 2*x + 3*x^2*(1-x^(2*n-2))/(1-x) - (n-2)*x^(2*n) - (n-1)*x^(2*n+1)).
The values of G(1) through G(6) (certified by MAGMA) are:
(1+x)^2/(1-x),
(x^3-2*x^2-1)*(1+x)^2/(x-1),
(2*x^5-3*x^4+x^3-2*x^2-1)*(1+x)^2/(x-1),
(3*x^7-4*x^6+2*x^5-3*x^4+x^3-2*x^2-1)*(1+x)^2/(x-1),
(4*x^9-5*x^8+3*x^7-4*x^6+2*x^5-3*x^4+x^3-2*x^2-1)*(1+x)^2/(x-1),
(5*x^11-6*x^10+4*x^9-5*x^8+3*x^7-4*x^6+2*x^5-3*x^4+x^3-2*x^2-1)*(1+x)^2/(x-1).
Note that row n is equal to 4*n once the (2*n+1)-st term has been reached.
The g.f.s for the rows can also be obtained by regarding the 1-skeleton of the cylinder as the Cayley diagram for an appropriate group H, and computing the growth function for H (see the MAGMA code).
Comments