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A329623 The absolute value of the difference between n and A053392(n), the concatenation of the sums of every pair of consecutive digits of n.

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%I A329623 #19 Dec 11 2019 08:01:09
%S A329623 0,1,2,3,4,5,6,7,8,9,9,9,9,9,9,9,9,9,9,9,18,18,18,18,18,18,18,18,18,
%T A329623 18,27,27,27,27,27,27,27,27,27,27,36,36,36,36,36,36,36,36,36,36,45,45,
%U A329623 45,45,45,45,45,45,45,45,54,54,54,54,54,54,54,54,54,54,63
%N A329623 The absolute value of the difference between n and A053392(n), the concatenation of the sums of every pair of consecutive digits of n.
%C A329623 As A040115 forms the basis of an iterative sequence leading to A329200 and A329201, this sequence forms the basis of a similar sequence A329624. As the concatenation of the digit sum can lead to a value larger than the original term we must take the absolute value of the difference to ensure subsequent terms are always positive. The largest value in the first 10000 terms is a(9991) = 171819.
%H A329623 Scott R. Shannon, <a href="/A329623/b329623.txt">Table of n, a(n) for n = 0..10000</a>
%e A329623 a(9) = 9 as A053392(9) = 0 and | 9 - 0 | = 9.
%e A329623 a(10) = 10 as A053392(10) = 1 and | 10 - 1 | = 9.
%e A329623 a(100) = 90 as A053392(100) = 10 and | 100 - 10 | = 90.
%e A329623 a(119) = 91 as A053392(119) = 210 and | 119 - 210 | = 91.
%p A329623 A329623 := proc(n)
%p A329623     abs(n-A053392(n)) ;
%p A329623 end proc: # _R. J. Mathar_, Dec 11 2019
%o A329623 (PARI) A329623(n)=abs(n-A053392(n)) \\ _M. F. Hasler_, Dec 02 2019
%Y A329623 Cf. A040115, A053392, A053393, A329200, A329201, A329624.
%K A329623 nonn,base
%O A329623 0,3
%A A329623 _Scott R. Shannon_, Nov 19 2019