A329809 Numbers k such that floor(k/10)^(k mod 10) contains the digit (k mod 10).

11, 26, 37, 39, 46, 52, 55, 56, 57, 59, 66, 67, 69, 73, 74, 76, 78, 84, 86, 87, 95, 97, 99, 101, 111, 112, 113, 114, 115, 116, 117, 118, 119, 121, 128, 129, 131, 136, 137, 138, 139, 141, 144, 145, 146, 148, 151, 152, 153, 155, 156, 157, 158, 159, 161, 162, 165, 166, 169, 171, 172, 173, 175

Offset: 1

Author

Eric Angelini and M. F. Hasler, Nov 21 2019

Keywords

• nonn
• base

Comments

Or: Numbers k such that A059995(k)^A010879(k) contains the last digit of k, A010879(k).

It's easy to see that all numbers ending in {11, 37, 46, 52, 55, 59, 66, 69, 73, 97, 99} are in the sequence: for these, A059995(k)^A010879(k) mod 100 = (1, 87, 96, 25, 25, 25, 56, 96, 43, 69, 89).

Links

• M. F. Hasler, in reply to Éric Angelini, 2019 must be read here as 201^9, SeqFan list, Nov. 21, 2019.

Crossrefs

Cf. A059995 (floor(n/10): drop final digit), A010879 (n mod 10; final digit of n).

Programs

PARI

select( t->setsearch(Set(digits((t\10)^(t%10))),t%10),[0..9999])