A330004 a(1) = 0, and for n > 0, a(n+1) = u - v where u (resp. v) is the number of terms equal to a(n) (resp. a(n)+1) among the first n terms.
0, 1, 1, 2, 1, 2, 2, 3, 1, 1, 2, 3, 2, 3, 3, 4, 1, 1, 2, 2, 3, 4, 2, 3, 4, 3, 4, 4, 5, 1, 0, -6, 1, 1, 2, 2, 3, 3, 4, 5, 2, 2, 3, 4, 5, 3, 4, 5, 4, 5, 5, 6, 1, -1, -1, 0, -8, 1, 0, -8, 2, 2, 3, 3, 4, 4, 5, 6, 2, 2, 3, 3, 4, 5, 6, 3, 4, 5, 6, 4, 5, 6, 5, 6, 6
Offset: 1
Examples
The first terms, alongside u and v, are: n a(n) u v -- ---- - - 1 0 1 0 2 1 1 0 3 1 2 0 4 2 1 0 5 1 3 1 6 2 2 0 7 2 3 0 8 3 1 0 9 1 4 3 10 1 5 3
Links
- Rémy Sigrist, Table of n, a(n) for n = 1..10000
- Rémy Sigrist, Density plot of the first 25000000 terms
Crossrefs
See A329981 for similar sequences.
Programs
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PARI
for (n=1, #(a=vector(85)), print1 (a[n]=if (n==1, 0, sum(k=1, n-1, (a[k]==a[n-1])-(a[k]==a[n-1]+1)))", "))
Comments