cp's OEIS Frontend

A330080 a(n) = floor(b(n)), where b(1) = b(2) = b(3) = 1 and b(n) = (b(n-1) + b(n-2))/b(n-3) for n > 3.

%I A330080 #18 Dec 10 2023 17:41:24
%S A330080 1,1,1,2,3,5,4,3,1,1,0,1,2,4,4,4,2,1,0,1,1,2,3,5,3,2,1,1,0,1,2,4,4,3,
%T A330080 1,1,0,1,1,3,4,4,2,1,0,1,1,2,3,5,3,2,1,1,0,1,2,4,4,3,1,1,0,1,1,3,4,4,
%U A330080 2,1,0,1,1,2,3,5,3,2,1,1,0,1,2,4,4,3,1,1,0,1,1,3,4,4,2,1,0,1,1,2,3,5
%N A330080 a(n) = floor(b(n)), where b(1) = b(2) = b(3) = 1 and b(n) = (b(n-1) + b(n-2))/b(n-3) for n > 3.
%C A330080 This sequence seems quasiperiodic with the same quasiperiod of A185332(n)/A185341(n) (see related comments of Michael Somos in A068508).
%C A330080 Conjecture: 0 <= a(n) <= 5.
%t A330080 c[1] = 1; c[2] = 1; c[3] = 1;
%t A330080 c[n_] := c[n] = (c[n - 2] + c[n - 1])/c[n - 3];
%t A330080 Table[Floor@c[j], {j, 1, 2^6}]
%Y A330080 Cf. A068508, A185332, A185341.
%K A330080 nonn
%O A330080 1,4
%A A330080 _Andres Cicuttin_, Nov 30 2019