A330090 Inverse permutation to A330081.
0, 1, 2, 3, 4, 6, 5, 7, 8, 12, 9, 13, 10, 14, 11, 15, 16, 24, 18, 26, 17, 25, 19, 27, 20, 28, 22, 30, 21, 29, 23, 31, 32, 48, 36, 52, 33, 49, 37, 53, 34, 50, 38, 54, 35, 51, 39, 55, 40, 56, 44, 60, 41, 57, 45, 61, 42, 58, 46, 62, 43, 59, 47, 63, 64, 96, 72
Offset: 0
Examples
A330081(19) = 22, hence a(22) = 19.
Links
Crossrefs
Cf. A330081.
Programs
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PARI
unshuffle(v) = { my (w=vector(#v), o=0, e=#v+1); for (k=1, #v, w[k]=v[if (k%2, o++, e--)]); w } a(n) = fromdigits(unshuffle(binary(n)), 2)
Comments