A333767 Length of shortest run of zeros after a one in the binary expansion of n. a(0) = 0.
0, 0, 1, 0, 2, 0, 0, 0, 3, 0, 1, 0, 0, 0, 0, 0, 4, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 5, 0, 1, 0, 2, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 6, 0, 1, 0, 2, 0, 0, 0, 2, 0, 1, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 0
Offset: 0
Keywords
Examples
The binary expansion of 148 is (1,0,0,1,0,1,0,0), so a(148) = 1.
Crossrefs
Positions of first appearances (ignoring index 0) are A000079.
Positions of terms > 0 are A022340.
Minimum prime index is A055396.
The maximum part minus 1 is given by A087117.
All of the following pertain to compositions in standard order (A066099):
- Length is A000120.
- Compositions without 1's are A022340.
- Sum is A070939.
- Product is A124758.
- Runs are counted by A124767.
- Strict compositions are A233564.
- Constant compositions are A272919.
- Runs-resistance is A333628.
- Maximum is A333766.
- Minimum is A333768.
- Weakly decreasing compositions are A114994.
- Weakly increasing compositions are A225620.
- Strictly decreasing compositions are A333255.
- Strictly increasing compositions are A333256.
Programs
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Mathematica
stc[n_]:=Differences[Prepend[Join@@Position[Reverse[IntegerDigits[n,2]],1],0]]//Reverse; Table[If[n==0,0,Min@@stc[n]-1],{n,0,100}]
Formula
For n > 0, a(n) = A333768(n) - 1.