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A334219 a(n) is the number of terms beyond the starting value n before a repeated number first appears when following the same rules as Recamán's sequence A005132 but starting at n instead of 0.

%I A334219 #22 Jan 14 2021 20:04:31
%S A334219 24,13,21,3,3,3,15,6,6,6,15,12,9,9,9,16,20,15,12,12,12,8,10,12,20,15,
%T A334219 15,15,10,15,24,22,26,18,18,18,11,13,18,29,28,27,21,21,21,15,13,19,17,
%U A334219 25,31,23,24,24,24,16,18,20,21,44,28,34,34,27,27,27,17,19,27,25,24
%N A334219 a(n) is the number of terms beyond the starting value n before a repeated number first appears when following the same rules as Recamán's sequence A005132 but starting at n instead of 0.
%C A334219 The first repeated number in each sequence starting from n is given in A334148.
%C A334219 The number of terms in each sequence starting from n required to reach a value greater than n given in A334149.
%C A334219 Essentially the same as A308419. - _R. J. Mathar_, May 06 2020
%H A334219 Scott R. Shannon, <a href="/A334219/b334219.txt">Table of n, a(n) for n = 0..10000</a>
%H A334219 Scott R. Shannon, <a href="/A334219/a334219.png">Plot of the terms for n = 0 to 1000000</a>
%H A334219 <a href="/index/Rea#Recaman">Index entries for sequences related to Recamán's sequence</a>
%e A334219 a(0) = 24 as a(0) corresponds to the standard Recamán's sequence A005132 in which the term 42 appears at A005132(20) and then again at A005132(24), taking twenty-four terms before the first repeated number appears.
%e A334219 a(4) = 3 as starting from 4 the sequence of visited numbers is 4,3,1,4 and it takes three steps beyond the start value for the first repeated number 4 to appear.
%e A334219 a(6) = 15 as starting from 6 the sequence of visited numbers is 6,5,3,0,4,9,15,8,16,7,17,28,40,27,13,28 and it takes fifteen steps beyond the start value for the first repeated number 28 to appear.
%Y A334219 Cf. A005132, A308419, A334148, A334149, A334225.
%K A334219 nonn
%O A334219 0,1
%A A334219 _Scott R. Shannon_, Apr 19 2020