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A338275 Array of triples read by antidiagonals of triples, giving analogs of Pythagorean triples [a,b,c] being [odd,even,odd] consistent with the functions U(i;n,k) described in A327263.

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%I A338275 #38 Jan 05 2022 10:50:57
%S A338275 5,8,9,5,12,13,15,12,19,5,16,17,21,20,29,9,24,25,5,20,21,27,28,39,9,
%T A338275 40,41,29,16,33,5,24,25,33,36,49,9,56,57,45,28,53,23,32,39,5,28,29,39,
%U A338275 44,59,9,72,73,61,40,73,33,56,65,13,48,49
%N A338275 Array of triples read by antidiagonals of triples, giving analogs of Pythagorean triples [a,b,c] being [odd,even,odd] consistent with the functions U(i;n,k) described in A327263.
%C A338275 In forming the triples we follow what we know about calculating Pythagorean triples given two positive integers m > n. That is, a = m^2 - n^2; b = 2m*n; c = m^2 + n^2. This is the case when i = 2. Here m is odd and n is even. The rows of triples are sorted by m then by n.
%C A338275 Within all rows of triples, each of a, b, and c are arithmetic progressions.
%C A338275 Within all rows of triples, consecutive triples have the same difference (delta) which is always an even multiple of a primitive Pythagorean triple.
%C A338275   delta_a = ((m-1)^2 - n^2)/2,
%C A338275   delta_b = (m-1)*n,
%C A338275   delta_c = ((m-1)^2 + n^2)/2.
%C A338275   When n = m - 1, delta_a = 0 while delta_b = delta_c, so delta_a^2 + delta_b^2 = delta_c^2 trivially.
%C A338275 In rows with n = m - 1, the following are true for all i:
%C A338275   a = m + n,
%C A338275   c = b + 1,
%C A338275   b + c = U(i; a, a).
%C A338275 Within all columns of triples, for each m, b is an arithmetic progression with difference 2m+2, a has a constant second difference of -4i and c has a constant second difference of +4i.
%C A338275 From _David Lovler_, Dec 04 2020: (Start)
%C A338275 If we modify the Pythagorean inradius formula according to the rules of U(i;odd,even), r = (m-n)*n becomes r = (i*(m-n)*n - (i-2)*n)/2. To distinguish this from the usual inradius let us call it the inradius computation or irc. The irc might not have a Euclidean interpretation, but using it brings light to the following theorem. Within a row of the table, the inradius of the (constant, Pythagorean) difference between consecutive triples equals the difference between the ircs of consecutive triples in the row, and both equal (m-n-1)*n/2.
%C A338275 Proof: The left hand side, according to A338895 and A338896, equals (m-n-1)*n/2. For the right hand side, given odd m and even n, irc(i+1) - irc(i) = U(i+1; m-n, n) - U(i; m-n, n) = ((i+1)*(m-n)*n - (i+1-2)*n)/2 - (i*(m-n)*n - (i-2)*n)/2 = (m-n-1)*n/2. (End)
%H A338275 Ron Knott, <a href="http://www.maths.surrey.ac.uk/hosted-sites/R.Knott/Pythag/pythag.html">Pythagorean Triples and Online Calculators</a>
%F A338275 Given i > 0, for each (odd,even) pair (m,n) with m >= 3 and m > n >= 2, the triple [a, b, c] consists of
%F A338275    a = (i*m^2 - (i-2)*(2m-1))/2 - (i*n^2)/2     analogous to m^2 - n^2
%F A338275    b =  i*m*n - (i-2)*n                         analogous to 2m*n
%F A338275    c = (i*m^2 - (i-2)*(2m-1))/2 + (i*n^2)/2     analogous to m^2 + n^2.
%e A338275 In the following start of the array, the column headings would be U(i;n,k), but n and k are left out to avoid confusion with n of (m,n).
%e A338275        U(1;,)       U(2;,)       U(3;,)        U(4;,)        U(5;,)       U(6;,)
%e A338275 m 3
%e A338275 n 2   [5,8,9]     [5,12,13]    [5,16,17]     [5,20,21]     [5,24,25]    [5,28,29]
%e A338275 -----------------------------------------------------------------------------------
%e A338275 m 5
%e A338275 n 2  [15,12,19]  [21,20,29]    [27,28,39]   [33,36,49]    [39,44,59]   [45,52,69]
%e A338275 n 4   [9,24,25]   [9,40,41]    [9,56,57]    [9,72,73]     [9,88,89]   [9,104,105]
%e A338275 -----------------------------------------------------------------------------------
%e A338275 m 7
%e A338275 n 2  [29,16,33]  [45,28,53]    [61,40,73]   [77,52,93]   [93,64,113]  [109,76,133]
%e A338275 n 4  [23,32,39]  [33,56,65]    [43,80,91]  [53,104,117] [63,128,143]  [73,152,169]
%e A338275 n 6  [13,48,49]  [13,84,85]   [13,120,121] [13,156,157] [13,192,193]  [13,228,229]
%e A338275 -----------------------------------------------------------------------------------
%e A338275 m 9
%e A338275 n 2  [47,20,51]  [77,36,85]   [107,52,119] [137,68,153] [167,84,187]  [197,100,221]
%e A338275 n 4  [41,40,57]  [65,72,97]  [89,104,137] [113,136,177] [137,168,217] [161,200,257]
%e A338275 n 6  [31,60,67] [45,108,117]  [59,156,167] [73,204,217] [87,252,267]  [101,300,317]
%e A338275 n 8  [17,80,81] [17,144,145]  [17,208,209] [17,272,273] [17,336,337]  [17,400,401]
%Y A338275 Cf. A338895, A338896.
%K A338275 nonn,tabf
%O A338275 1,1
%A A338275 _David Lovler_, Oct 19 2020