A338626 a(n) is the least k such that the first k terms of the Kolakoski sequence (A000002) contain a length-n repeated block.
3, 6, 9, 10, 13, 15, 16, 28, 32, 33, 40, 41, 42, 43, 69, 70, 71, 72, 94, 95, 96, 97, 98, 99, 106, 107, 108, 109, 214, 215, 216, 217, 218, 219, 220, 221, 222, 297, 298, 299, 300, 301, 339, 340, 487, 719, 720, 721, 722, 723, 724, 725, 726, 727, 728, 729, 730
Offset: 1
Keywords
Examples
For n = 2: - the first 5 terms of Kolakoski sequence are: 1, 2, 2, 1, 1, - they have no length-2 repeated block, - the first 6 terms of Kolakoski sequence are: 1, 2, 2, 1, 1, 2, - they have a length-2 repeated block: 1, 2, - so a(2) = 6.
Links
- Rémy Sigrist, Table of n, a(n) for n = 1..9511 (terms < 3000000)
- Rémy Sigrist, PARI program for A338626
- Rémy Sigrist, Perl program for A338626
Programs
-
PARI
See Links section.
-
Perl
See Links section.
Formula
A338624(a(n)) = n.
Comments