A338923 Every even term k of the sequence is the cumulative sum of the even digits used so far (the digits of k are included in the sum).
0, 1, 2, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 10, 12, 29, 31, 33, 35, 37, 39, 41, 20, 43, 45, 47, 49, 40, 51, 53, 55, 57, 59, 61, 63, 65, 67, 69, 70, 71, 72, 73, 75, 77, 79, 80, 81, 83, 85, 87, 89, 91, 93, 95, 97, 99, 101, 103, 105, 107, 109, 111, 113, 115, 117, 119, 121, 123, 125, 127, 129, 130
Offset: 1
Examples
a(1) = 0 as 0 is the sum of all even digits used so far: a(2) = 1 as 1 is the smallest term not yet present in the sequence that doesn't lead to a contradiction; a(3) = 2 as 2 is the sum of all even digits used so far (0 + 2); a(4) = 3 as 3 is the smallest term not yet present in the sequence that doesn't lead to a contradiction; ... a(17) = 10 as 10 is the sum of all even digits used so far (0 + 2 + 2 + 2 + 2 + 2 + 0); a(18) = 12 as 12 is the sum of all even digits used so far (0 + 2 + 2 + 2 + 2 + 2 + 0 + 2); a(19) = 29 as 29 is the smallest term not yet present in the sequence that doesn't lead to a contradiction; etc.
Links
- Carole Dubois, Table of n, a(n) for n = 1..5000
Programs
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PARI
my(v=[], S=0,p=1, n=1);while(n<100, c=0;for(q=S, p, if(!(q%2), m=0;for(i=1,#digits(q),if(!(digits(q)[i]%2),m+=digits(q)[i]));if(S+m==q&&!vecsearch(vecsort(v), q),v=concat(v, q); S+=m; c++; break))); if(c==0, for(j=1,#digits(p),if(!(digits(p)[j]%2),S+=digits(p)[j])); v=concat(v, p); p+=2); n++); v \\ Derek Orr, Nov 22 2020
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