A339975 a(n) is the number of 0's minus the number of 1's among the first n terms of A337546.

0, 1, 0, 1, 2, 1, 0, 1, 0, 1, 2, 1, 2, 1, 0, 1, 2, 1, 2, 3, 2, 1, 2, 1, 2, 3, 2, 3, 2, 1, 2, 1, 2, 3, 2, 1, 2, 1, 0, 1, 2, 1, 2, 1, 0, 1, 0, 1, 2, 1, 0, 1, 2, 1, 2, 1, 0, 1, 2, 1, 0, 1, 0, 1, 2, 1, 0, 1, 2, 1, 2, 1, 0, 1, 0, 1, 2, 1, 0, 1, 0, -1, 0, 1, 0, 1, 0

Offset: 0

Author

Rémy Sigrist, Dec 25 2020

Keywords

• sign

Comments

See A339976 for the positions of 0's.

Examples

			For n = 5, the first 5 terms of A337546 are 0, 1, 0, 0, 1, so a(5) = 3 - 2 = 1.
		

Links

• Rémy Sigrist, Table of n, a(n) for n = 0..10000
• Rémy Sigrist, C program for A339975

Crossrefs

Cf. A294448, A337546, A339976.

Programs

C

See Links section.

Formula

a(n) = Sum_{k = 1..n} (-1)^A337546(n).

a(n) = n - 2*Sum_{k = 1..n} A337546(n).