A340064 Every odd term k of the sequence is the cumulative sum of the prime digits used so far (the digits of k are included in the sum).
3, 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 9, 22, 24, 26, 28, 19, 21, 30, 32, 34, 36, 38, 40, 42, 43, 44, 46, 48, 50, 52, 54, 63, 73, 56, 58, 60, 62, 64, 66, 68, 70, 72, 101, 74, 76, 78, 80, 82, 84, 86, 88, 90, 92, 94, 96, 98, 100, 102, 131, 104, 106, 108, 110, 112, 114, 116, 118, 120, 122, 124, 141, 126, 128, 153
Offset: 1
Examples
Not a(1) = 1 as this 1, being odd, should be the sum of the prime digits so far -- which is wrong (there are none); not a(1) = 2 as a(1) = 3 is odd and possible here; a(12) = 9 as 9 is odd and the sum of the prime digits 3 + 2 + 2 + 2; a(13) = 22 as 22 is the smallest even term available; a(17) = 19 as 19 = 3 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2; a(18) = 21 as 21 is the sum of 19 + 2 (the first digit of 21 itself); etc.
Crossrefs
CF. A338924
Programs
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Python
def pds(k): return sum(int(d) for d in str(k) if d in "2357") def aupto(nn): aset, alst, primesum, nexteven = set(), [], 0, 2 for n in range(1, nn): k = 1 found = False while not found: while k in aset: k += 2 if k == primesum + pds(k): found = True; break if k > primesum + 7 * len(str(k)): break k += 2 if found: ak = k else: ak = nexteven; nexteven += 2 aset.add(ak); alst.append(ak); primesum += pds(ak) return alst print(aupto(76)) # Michael S. Branicky, Dec 29 2020
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