cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A340206 Constant whose decimal expansion is the concatenation of the smallest n-digit square A061432(n), for n = 1, 2, 3, ...

Original entry on oeis.org

1, 1, 6, 1, 0, 0, 1, 0, 2, 4, 1, 0, 0, 0, 0, 1, 0, 0, 4, 8, 9, 1, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 4, 5, 6, 9, 1, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 4, 1, 2, 9, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 4, 7, 9, 8, 4, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 2, 1, 4, 9, 2, 8, 4, 1, 0, 0, 0, 0
Offset: 0

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Author

M. F. Hasler, Dec 31 2020

Keywords

Comments

The terms of sequence A215689 have this as limit, digit-wise and as a constant, up to powers of 10.
Every other "smallest n-digit square" (i.e., for odd n = 2k + 1) is 10^k, which explains the chunks of (1,0,...,0), cf. formula.

Examples

			The smallest square with 1, 2, 3, 4, ... digits is, respectively, 1, 16 = 4^2, 100 = 10^2, 1024 = 32^2, ....
Here we list the digits of these numbers: 1; 1, 6; 1, 0, 0; 1, 0, 2, 4; ...
As for the Champernowne and Copeland-Erdős constants, we can consider this as the decimal expansion of the real constant 0.116100102410000100489...
		

Crossrefs

Cf. A061432 (smallest n-digit squares), A215689 (has this as "limit"), A340207 (same for largest n-digit squares), A340208 (same for cubes), A340219 (same for primes), A340221 (same for semiprimes).
Cf. A033307 (Champernowne constant), A030190 (binary), A001191 (concatenation of all squares), A134724 (cubes), A033308 (primes: Copeland-Erdős constant).

Programs

  • PARI
    concat([digits(ceil(10^((k-1)/2))^2)|k<-[1..14]]) \\ as seq. of digits
    c(N=20)=sum(k=1,N,.1^(k*(k+1)/2)*ceil(10^((k-1)/2))^2) \\ as constant

Formula

c = 0.11610010241000010048910000001000456910000000010000141291000000000010...
= Sum_{k >= 1} 10^(-k(k+1)/2)*ceiling(10^((k-1)/2))^2
a(-n(n+1)/2) = 1 for all n >= 0; a(k) = 0 for -n(n-1)/2 > k > -n(n+1)/2 with odd n.