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A341658 Primes p such that p^2 - 1 has 32 divisors.

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%I A341658 #15 Jun 14 2024 19:00:18
%S A341658 29,43,53,59,61,67,83,107,157,173,193,227,277,283,317,347,563,653,733,
%T A341658 787,877,907,997,1213,1237,1283,1307,1523,1867,2083,2693,2797,2803,
%U A341658 3253,3413,3517,3643,3677,3733,3803,4253,4363,4547,4723,5387,5443,5483,5717
%N A341658 Primes p such that p^2 - 1 has 32 divisors.
%C A341658 Conjecture: sequence is infinite.
%C A341658 All terms are primes p such that p^2 - 1 is of the form 24*q*r = 2^3 * 3 * q * r (where q and r are distinct primes), with only three exceptions: 53, 107, and 193 (see Example section).
%C A341658 For primes p > 3, p^2 - 1 = (p-1)*(p+1) will have p-1 and p+1 as consecutive even numbers (so one of them is divisible by 4, so their product is divisible by 8), and one of p-1 and p+1 will be divisible by 3. For each term other than 53, 107, and 193, the factors p-1 and p+1 are, in some order, numbers of the forms 2*q and 12*r or 4*q and 6*r.
%e A341658       p =               factorization
%e A341658    n  a(n)  p^2 - 1      of (p^2 - 1)
%e A341658   --  ----  -------  -------------------
%e A341658    1   29      840   2^3 * 3   *  5 *  7
%e A341658    2   43     1848   2^3 * 3   *  7 * 11
%e A341658    3   53     2808   2^3 * 3^3 * 13
%e A341658    4   59     3480   2^3 * 3   *  5 * 29
%e A341658    5   61     3720   2^3 * 3   *  5 * 31
%e A341658    6   67     4488   2^3 * 3   * 11 * 17
%e A341658    7   83     6888   2^3 * 3   *  7 * 41
%e A341658    8  107    11448   2^3 * 3^3 * 53
%e A341658    9  157    24648   2^3 * 3   * 13 * 79
%e A341658   10  173    29928   2^3 * 3   * 29 * 43
%e A341658   11  193    37248   2^7 * 3   * 97
%t A341658 Select[Range[6000], PrimeQ[#] && DivisorSigma[0, #^2 - 1] == 32 &] (* _Amiram Eldar_, Feb 26 2021 *)
%o A341658 (PARI) isok(p) = isprime(p) && (numdiv(p^2-1) == 32); \\ _Michel Marcus_, Feb 26 2021
%Y A341658 Cf. A000005, A000040, A309906, A341655.
%K A341658 nonn
%O A341658 1,1
%A A341658 _Jon E. Schoenfield_, Feb 26 2021