A341825 Number of finite groups G with |Aut(G)| = n.
2, 3, 0, 4, 0, 6, 0, 7, 0, 2, 0, 9, 0, 0, 0, 11, 0, 4, 0, 7, 0, 2, 0, 22, 0, 0, 0, 2, 0, 2, 0, 19, 0, 0, 0, 12, 0, 0, 0, 14, 0, 7, 0, 3, 0, 2, 0
Offset: 1
Examples
a(6) = 6, because there are six groups G with |Aut(G)| = 6. Four cyclic groups: Aut(C_7) = Aut(C_9) = Aut(C_14) = Aut(C_18) ~~ C_6, and also Aut(C_2 x C_2) = Aut(S_3) ~~ S_3, where ~~ stands for “isomorphic to”. - _Bernard Schott_, Mar 02 2021 a(8) = 7, because there are seven groups G with |Aut(G)| = 8.
Links
- D. MacHale and R. Sheehy, Finite groups with few automorphisms, Mathematical Proceedings of the Royal Irish Academy, Vol. 104A, No. 2 (December 2004), 231-238.
Formula
a(2) = 3, a(p) = 0 if p odd prime.
a(A002202(n)) > 0, since |Aut(C_n)| = phi(n).
Comments