A342375 Number of commutative rings without 1 containing n elements.
0, 1, 1, 5, 1, 3, 1, 24, 5, 3, 1, 14, 1, 3, 3, 125, 1, 14, 1, 14, 3, 3, 1, 58, 5, 3, 25, 14, 1, 7, 1
Offset: 1
Examples
a(1) = 0 because the only ring with 1 element is the zero ring with the element 0, and for this ring, 0 and 1 coincide. a(2) = 1, and for this corresponding ring with elements {0,a}, the multiplication that is defined by: 0*0 = 0*a = a*0 = a*a = 0 is commutative, also this ring is without unit, hence a(2) = 1; the Matrix ring {0,a} with coefficients from Z/2Z: (0 0) (0 0) 0 = (0 0) a = (1 0) is such an example. For n=8, there are 52 rings of order 8, 24 of which are commutative rings without 1, so a(8) = 24.
Links
- Wikipedia, Pseudo-ring.
- Wikipedia, Rng.
- Index to sequences related to rings.
Comments