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A342446 Square table read by antidiagonals downwards: T(n,k) = floor((4/(4^(1/2^n)-1))^(1/2^k)).

%I A342446 #24 Apr 13 2021 10:53:29
%S A342446 1,4,1,9,2,1,21,3,1,1,44,4,1,1,1,90,6,2,1,1,1,182,9,2,1,1,1,1,367,13,
%T A342446 3,1,1,1,1,1,736,19,3,1,1,1,1,1,1,1475,27,4,1,1,1,1,1,1,1,2952,38,5,2,
%U A342446 1,1,1,1,1,1,1,5907,54,6,2,1,1,1,1,1,1,1,1
%N A342446 Square table read by antidiagonals downwards: T(n,k) = floor((4/(4^(1/2^n)-1))^(1/2^k)).
%C A342446 Every positive integer occurs infinitely often.
%H A342446 N. J. Fine and Marcin E. Kuczma, <a href="https://www.jstor.org/stable/2324192"> Writing Integers with Exactly Three Fours, Problem E 3363 [1990, 63]</a>, Amer. Math. Monthly, Vol. 99 (1992), No. 2, pp. 163-164.
%F A342446 T(n,k) = floor((4/(4^(1/2^n)-1))^(1/2^k)).
%e A342446 T(2,1) = floor((4/(4^(1/4)-1))^(1/2)) = floor(sqrt(4/(sqrt(2)-1))) = floor(3.1075...) = 3.
%K A342446 nonn,tabl
%O A342446 0,2
%A A342446 _Franz Vrabec_, Mar 12 2021