A342999 a(n) is always followed by the concatenation of a(n)'s distinct prime factors in increasing order. If this concatenation is already in the sequence, a(n+1) is the smallest term not yet present.
1, 2, 3, 4, 5, 6, 23, 7, 8, 9, 10, 25, 11, 12, 13, 14, 27, 15, 35, 57, 319, 1129, 16, 17, 18, 19, 20, 21, 37, 22, 211, 24, 26, 213, 371, 753, 3251, 28, 29, 30, 235, 547, 31, 32, 33, 311, 34, 217, 731, 1743, 3783, 31397, 36, 38, 219, 373, 39, 313, 40, 41, 42, 237, 379, 43, 44, 45, 46, 223, 47
Offset: 1
Examples
a(6) is not = 5, though the only prime factor of a(5) is precisely 5; but as 5 is already in the sequence we must take a(6) = 6, the smallest term not yet present in the sequence. a(7) = 23 as the prime factors of a(6) = 6 are 2 and 3, which, concatenated in increasing order, give 23; a(8) is not = 23, though the only prime factor of a(7) is precisely 23; but as 23 is already in the sequence we must take a(8) = 7, the smallest term not yet present in the sequence; etc.
Crossrefs
Programs
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Mathematica
a[1]=1;a[n_]:=a[n]=(g=FromDigits@Flatten[IntegerDigits@*First/@FactorInteger@a[n-1]];If[FreeQ[k=Array[a,n-1],g],g,Min@Complement[Range@Max[k+1],k]]) Array[a,100] (* Giorgos Kalogeropoulos, Apr 02 2021 *)
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Python
from sympy import primefactors def aupton(terms): alst, aset = [1, 2], {1, 2} while len(alst) < terms: an = int("".join(map(str, primefactors(alst[-1])))) if an in aset: an = 1 while an in aset: an += 1 alst.append(an); aset.add(an) return alst[:terms] print(aupton(100)) # Michael S. Branicky, Apr 02 2021
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