A343460 Number of ways to write n as x^6 + y^3 + z*(3*z+1)/2 + 2^k, where x and y are nonnegative integers, z is an integer and k is a positive integer.
0, 1, 3, 5, 6, 5, 4, 4, 6, 9, 8, 6, 5, 5, 6, 7, 11, 11, 7, 5, 5, 5, 5, 8, 8, 5, 4, 5, 7, 7, 10, 11, 7, 8, 8, 8, 8, 9, 10, 8, 6, 7, 10, 10, 10, 7, 6, 7, 4, 5, 7, 6, 5, 4, 7, 8, 6, 5, 7, 8, 7, 6, 3, 5, 8, 12, 15, 13, 12, 10, 9, 11, 17, 18, 13, 9, 6, 9, 11, 16
Offset: 1
Keywords
Examples
a(2) = 1 with 2 = 0^6 + 0^3 + 0*(3*0+1)/2 + 2^1. a(175) = 2 with 175 = 1^6 + 3^3 + (-10)*(3*(-10)+1)/2 + 2^1 = 2^6 + 4^3 + 3*(3*3+1)/2 + 2^5. a(14553) = 1 with 14553 = 2^6 + 17^3 + (-80)*(3*(-80)+1)/2 + 2^4.
Links
- Zhi-Wei Sun, Table of n, a(n) for n = 1..10000
Programs
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Mathematica
PenQ[n_]:=PenQ[n]=IntegerQ[Sqrt[24n+1]]; tab={};Do[r=0;Do[If[PenQ[n-x^6-y^3-2^k],r=r+1],{x,0,(n-1)^(1/6)},{y,0,(n-x^6-1)^(1/3)},{k,1,Log[2,n-x^6-y^3]}];tab=Append[tab,r],{n,1,80}];Print[tab]
Comments