cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A344141 Lexicographically first irreducible polynomial over GF(2) of degree n, evaluated at X = 2.

Original entry on oeis.org

2, 7, 11, 19, 37, 67, 131, 283, 515, 1033, 2053, 4105, 8219, 16417, 32771, 65579, 131081, 262153, 524327, 1048585, 2097157, 4194307, 8388641, 16777243, 33554441, 67108891, 134217767, 268435459, 536870917, 1073741827, 2147483657, 4294967437, 8589934667
Offset: 1

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Author

Jianing Song, May 10 2021

Keywords

Comments

a(n) is the smallest term in A014580 that is greater than or equal to 2^n.
To get a(n), you first ask the question: "Is x^n irreducible over GF(2)?" If it is not, you then ask "is x^n + 1 irreducible over GF(2)", then "is x^n + x irreducible over GF(2)", then "is x^n + x + 1 irreducible over GF(2)", until you get an irreducible polynomial, then evaluate it at x = 2.
Note that in general you do not get an irreducible polynomial with the lowest possible number of terms, see A344142 and A344143.
N | The smallest n with | The corresponding polynomial of degree n
| A000120(a(n)) = N |
1 | 1 | x
3 | 2 | x^2 + x + 1
5 | 8 | x^8 + x^4 + x^3 + x + 1
7 | 37 | x^37 + x^5 + x^4 + x^3 + x^2 + x + 1
9 | 149 | x^149 + x^9 + x^7 + x^6 + x^5 + x^4 + x^3 + x + 1
In A057496 it is stated that if x^n + x^3 + x^2 + x + 1 is irreducible, then so is x^n + x^3 + 1. It follows that no term other than 19 can be of the form 2^n + 15.

Examples

			a(8) = 283, since x^8, x^8 + 1, x^8 + x, x^8 + x + 1, ..., x^8 + x^4 + x^3 + x are all reducible over GF(2) and x^8 + x^4 + x^3 + x + 1 is irreducible, so a(8) = 2^8 + 2^4 + 2^3 + 2 + 1 = 283.
a(33) = 8589934667, since x^33, x^33 + 1, x^33 + x, x^33 + x + 1, ..., x^33 + x^6 + x^3 + x are all reducible over GF(2) and x^33 + x^6 + x^3 + x + 1 is irreducible, so a(33) = 2^33 + 2^6 + 2^3 + 2 + 1 = 8589934667. Note that there is an irreducible trinomial of degree 33, namely x^33 + x^10 + 1.
		

Crossrefs

Programs

  • PARI
    A344141(n) = for(k=2^n, 2^(n+1)-1, if(polisirreducible(Mod(Pol(binary(k)), 2)), return(k)))

A344142 Lexicographically first irreducible polynomial over GF(2) of degree n with the lowest possible number of terms, evaluated at X = 2.

Original entry on oeis.org

2, 7, 11, 19, 37, 67, 131, 283, 515, 1033, 2053, 4105, 8219, 16417, 32771, 65579, 131081, 262153, 524327, 1048585, 2097157, 4194307, 8388641, 16777243, 33554441, 67108891, 134217767, 268435459, 536870917, 1073741827, 2147483657, 4294967437, 8589935617
Offset: 1

Views

Author

Jianing Song, May 10 2021

Keywords

Comments

Different from A344141, here you first check x^n + x + 1, x^n + x^2 + 1, ..., x^n + x^(n-1) + 1 until you get an irreducible polynomial over GF(2); if there are none, you then check x^n + x^3 + x^2 + x + 1, x^n + x^4 + x^2 + x + 1, x^n + x^4 + x^3 + x + 1, x^n + x^4 + x^3 + x^2 + 1, ..., x^n + x^(n-1) + x^(n-2) + x^(n-3) + 1 until you get an irreducible polynomial over GF(2). Once you find it, evaluate it at x = 2.
Note that it is conjectured that an irreducible polynomial of degree n with 5 terms exists for every n. It follows from the conjecture that A000120(a(n)) = 3 for n in A073571 and 5 for n in A057486.
In A057496 it is stated that if x^n + x^3 + x^2 + x + 1 is irreducible, then so is x^n + x^3 + 1. It follows that no term other than 19 can be of the form 2^n + 15.

Examples

			a(33) = 8589935617, since x^33 + x + 1, x^33 + x^2 + 1, x^33 + x^3 + 1, ..., x^33 + x^9 + 1 are all reducible over GF(2) and x^33 + x^10 + 1 is irreducible, so a(33) = 2^33 + 2^10 + 1 = 8589935617.
a(8) = 283, since x^8 + x + 1, x^8 + x^2 + 1, ..., x^8 + x^7 + 1 are all reducible over GF(2); both x^8 + x^3 + x^2 + x + 1, x^8 + x^4 + x^2 + x + 1 are reducible, and x^8 + x^4 + x^3 + x + 1 is irreducible, so a(8) = 2^8 + 2^4 + 2^3 + 2 + 1 = 283.
		

Crossrefs

Programs

  • PARI
    A344142(n) = if(n==1, 2, for(k=1, n-1, if(polisirreducible(Mod(x^n+x^k+1, 2)), return(2^n+2^k+1))); for(a=3, n-1, for(b=2, a-1, for(c=1, b-1, if(polisirreducible(Mod(x^n+x^a+x^b+x^c+1, 2)), return(2^n+2^a+2^b+2^c+1)))))) \\ Assuming that an irreducible polynomial of degree n with at most 5 terms exists for every n.
Showing 1-2 of 2 results.