cp's OEIS Frontend

A344862 Numbers that are the sum of three fourth powers in ten or more ways.

%I A344862 #10 Jul 31 2021 18:29:31
%S A344862 49511121842,281539574498,364765611938,401069383442,541692688082,
%T A344862 703409488418,792177949472,971024246738,1067666696642,1090123576178,
%U A344862 1315120863602,1383280118402,1442012945282,1561211646722,1828395925538,1868287026242,1872511131218,2054230720178
%N A344862 Numbers that are the sum of three fourth powers in ten or more ways.
%H A344862 David Consiglio, Jr., <a href="/A344862/b344862.txt">Table of n, a(n) for n = 1..21</a>
%e A344862 49511121842 is a term because 49511121842 = 13^4 + 390^4 + 403^4  = 35^4 + 378^4 + 413^4  = 70^4 + 357^4 + 427^4  = 103^4 + 335^4 + 438^4  = 117^4 + 325^4 + 442^4  = 137^4 + 310^4 + 447^4  = 175^4 + 322^4 + 441^4  = 182^4 + 273^4 + 455^4  = 202^4 + 255^4 + 457^4  = 225^4 + 233^4 + 458^4.
%o A344862 (Python)
%o A344862 from itertools import combinations_with_replacement as cwr
%o A344862 from collections import defaultdict
%o A344862 keep = defaultdict(lambda: 0)
%o A344862 power_terms = [x**4 for x in range(1, 1000)]
%o A344862 for pos in cwr(power_terms, 3):
%o A344862     tot = sum(pos)
%o A344862     keep[tot] += 1
%o A344862 rets = sorted([k for k, v in keep.items() if v >= 10])
%o A344862 for x in range(len(rets)):
%o A344862     print(rets[x])
%Y A344862 Cf. A344750, A344861, A344928, A345121.
%K A344862 nonn
%O A344862 1,1
%A A344862 _David Consiglio, Jr._, May 31 2021