cp's OEIS Frontend

A344940 Numbers that are the sum of five fourth powers in six or more ways.

%I A344940 #8 Jul 31 2021 18:13:28
%S A344940 151300,197779,211059,217154,225890,236194,236675,243235,246674,
%T A344940 250834,286114,288579,300835,302130,302210,303235,309059,317795,
%U A344940 320195,334819,334899,335443,336210,338914,346835,356899,363379,366995,373234,375619,389875,391154
%N A344940 Numbers that are the sum of five fourth powers in six or more ways.
%H A344940 David Consiglio, Jr., <a href="/A344940/b344940.txt">Table of n, a(n) for n = 1..10000</a>
%e A344940 151300 is a term because 151300 = 3^4 + 3^4 + 3^4 + 12^4 + 19^4  = 3^4 + 11^4 + 11^4 + 14^4 + 17^4  = 3^4 + 13^4 + 13^4 + 13^4 + 16^4  = 6^4 + 9^4 + 9^4 + 9^4 + 19^4  = 7^4 + 11^4 + 11^4 + 11^4 + 18^4  = 8^4 + 9^4 + 13^4 + 13^4 + 17^4.
%o A344940 (Python)
%o A344940 from itertools import combinations_with_replacement as cwr
%o A344940 from collections import defaultdict
%o A344940 keep = defaultdict(lambda: 0)
%o A344940 power_terms = [x**4 for x in range(1, 1000)]
%o A344940 for pos in cwr(power_terms, 5):
%o A344940     tot = sum(pos)
%o A344940     keep[tot] += 1
%o A344940 rets = sorted([k for k, v in keep.items() if v >= 6])
%o A344940 for x in range(len(rets)):
%o A344940     print(rets[x])
%Y A344940 Cf. A344358, A344904, A344941, A344942, A345174, A345563, A345864.
%K A344940 nonn
%O A344940 1,1
%A A344940 _David Consiglio, Jr._, Jun 03 2021