cp's OEIS Frontend

A345514 Numbers that are the sum of six cubes in five or more ways.

%I A345514 #6 Aug 05 2021 15:23:56
%S A345514 1045,1169,1241,1260,1377,1384,1432,1440,1488,1495,1530,1539,1549,
%T A345514 1556,1558,1584,1586,1594,1595,1602,1612,1617,1640,1647,1654,1657,
%U A345514 1673,1675,1677,1703,1710,1712,1715,1719,1729,1736,1738,1745,1747,1754,1764,1766,1771
%N A345514 Numbers that are the sum of six cubes in five or more ways.
%H A345514 Sean A. Irvine, <a href="/A345514/b345514.txt">Table of n, a(n) for n = 1..10000</a>
%e A345514 1169 is a term because 1169 = 1^3 + 2^3 + 2^3 + 3^3 + 4^3 + 9^3 = 1^3 + 2^3 + 5^3 + 5^3 + 5^3 + 7^3 = 1^3 + 3^3 + 4^3 + 4^3 + 4^3 + 8^3 = 2^3 + 3^3 + 3^3 + 4^3 + 5^3 + 8^3 = 3^3 + 3^3 + 3^3 + 3^3 + 7^3 + 7^3.
%o A345514 (Python)
%o A345514 from itertools import combinations_with_replacement as cwr
%o A345514 from collections import defaultdict
%o A345514 keep = defaultdict(lambda: 0)
%o A345514 power_terms = [x**3 for x in range(1, 1000)]
%o A345514 for pos in cwr(power_terms, 6):
%o A345514     tot = sum(pos)
%o A345514     keep[tot] += 1
%o A345514     rets = sorted([k for k, v in keep.items() if v >= 5])
%o A345514     for x in range(len(rets)):
%o A345514         print(rets[x])
%Y A345514 Cf. A343989, A344809, A345513, A345515, A345523, A345562, A345767.
%K A345514 nonn
%O A345514 1,1
%A A345514 _David Consiglio, Jr._, Jun 20 2021