cp's OEIS Frontend

A345543 Numbers that are the sum of nine cubes in four or more ways.

%I A345543 #6 Aug 05 2021 15:19:07
%S A345543 224,257,264,283,320,348,355,372,374,376,381,383,390,400,402,407,409,
%T A345543 411,413,414,416,428,435,439,442,446,450,453,454,461,465,472,474,476,
%U A345543 479,481,486,488,491,498,500,502,503,505,507,509,510,512,514,517,519,524
%N A345543 Numbers that are the sum of nine cubes in four or more ways.
%H A345543 Sean A. Irvine, <a href="/A345543/b345543.txt">Table of n, a(n) for n = 1..10000</a>
%e A345543 257 is a term because 257 = 1^3 + 1^3 + 1^3 + 1^3 + 1^3 + 1^3 + 1^3 + 4^3 + 4^3 = 1^3 + 1^3 + 1^3 + 1^3 + 1^3 + 1^3 + 2^3 + 3^3 + 5^3 = 1^3 + 1^3 + 1^3 + 2^3 + 3^3 + 3^3 + 3^3 + 3^3 + 3^3 = 1^3 + 2^3 + 2^3 + 2^3 + 2^3 + 2^3 + 3^3 + 3^3 + 4^3.
%o A345543 (Python)
%o A345543 from itertools import combinations_with_replacement as cwr
%o A345543 from collections import defaultdict
%o A345543 keep = defaultdict(lambda: 0)
%o A345543 power_terms = [x**3 for x in range(1, 1000)]
%o A345543 for pos in cwr(power_terms, 9):
%o A345543     tot = sum(pos)
%o A345543     keep[tot] += 1
%o A345543     rets = sorted([k for k, v in keep.items() if v >= 4])
%o A345543     for x in range(len(rets)):
%o A345543         print(rets[x])
%Y A345543 Cf. A345501, A345534, A345542, A345544, A345552, A345588, A345796.
%K A345543 nonn
%O A345543 1,1
%A A345543 _David Consiglio, Jr._, Jun 20 2021