cp's OEIS Frontend

A345548 Numbers that are the sum of nine cubes in nine or more ways.

%I A345548 #6 Aug 05 2021 15:19:25
%S A345548 859,861,896,903,922,929,935,939,959,966,971,973,978,985,992,997,999,
%T A345548 1004,1009,1011,1016,1018,1020,1022,1023,1027,1029,1030,1034,1035,
%U A345548 1036,1037,1041,1046,1048,1055,1056,1059,1060,1062,1063,1064,1065,1066,1067,1071
%N A345548 Numbers that are the sum of nine cubes in nine or more ways.
%H A345548 Sean A. Irvine, <a href="/A345548/b345548.txt">Table of n, a(n) for n = 1..10000</a>
%e A345548 861 is a term because 861 = 1^3 + 1^3 + 1^3 + 1^3 + 1^3 + 1^3 + 1^3 + 4^3 + 8^3 = 1^3 + 1^3 + 1^3 + 1^3 + 1^3 + 3^3 + 3^3 + 5^3 + 7^3 = 1^3 + 1^3 + 2^3 + 2^3 + 4^3 + 4^3 + 4^3 + 4^3 + 6^3 = 1^3 + 1^3 + 3^3 + 3^3 + 3^3 + 3^3 + 3^3 + 3^3 + 7^3 = 1^3 + 2^3 + 2^3 + 2^3 + 2^3 + 2^3 + 3^3 + 3^3 + 8^3 = 1^3 + 2^3 + 2^3 + 2^3 + 3^3 + 4^3 + 4^3 + 5^3 + 6^3 = 2^3 + 2^3 + 2^3 + 2^3 + 3^3 + 3^3 + 5^3 + 5^3 + 6^3 = 2^3 + 2^3 + 2^3 + 2^3 + 3^3 + 3^3 + 3^3 + 4^3 + 7^3 = 3^3 + 3^3 + 3^3 + 3^3 + 4^3 + 4^3 + 4^3 + 4^3 + 5^3.
%o A345548 (Python)
%o A345548 from itertools import combinations_with_replacement as cwr
%o A345548 from collections import defaultdict
%o A345548 keep = defaultdict(lambda: 0)
%o A345548 power_terms = [x**3 for x in range(1, 1000)]
%o A345548 for pos in cwr(power_terms, 9):
%o A345548     tot = sum(pos)
%o A345548     keep[tot] += 1
%o A345548     rets = sorted([k for k, v in keep.items() if v >= 9])
%o A345548     for x in range(len(rets)):
%o A345548         print(rets[x])
%Y A345548 Cf. A345539, A345547, A345549, A345557, A345593, A345801.
%K A345548 nonn
%O A345548 1,1
%A A345548 _David Consiglio, Jr._, Jun 20 2021