cp's OEIS Frontend

A345551 Numbers that are the sum of ten cubes in three or more ways.

%I A345551 #6 Aug 05 2021 15:16:41
%S A345551 197,225,232,239,246,251,253,258,260,265,267,272,277,279,281,284,286,
%T A345551 288,291,293,295,298,300,302,303,305,307,309,310,312,314,316,317,319,
%U A345551 321,323,324,326,328,329,330,335,336,338,340,342,343,344,345,347,349,351
%N A345551 Numbers that are the sum of ten cubes in three or more ways.
%H A345551 Sean A. Irvine, <a href="/A345551/b345551.txt">Table of n, a(n) for n = 1..10000</a>
%e A345551 225 is a term because 225 = 1^3 + 1^3 + 1^3 + 1^3 + 1^3 + 1^3 + 1^3 + 1^3 + 1^3 + 5^3 = 1^3 + 1^3 + 1^3 + 1^3 + 1^3 + 1^3 + 3^3 + 3^3 + 3^3 + 3^3 = 1^3 + 1^3 + 1^3 + 1^3 + 2^3 + 2^3 + 2^3 + 2^3 + 3^3 + 4^3 = 1^3 + 2^3 + 3^3 + 3^3 + 3^3 + 3^3 + 3^3 + 3^3 + 3^3 + 3^3.
%o A345551 (Python)
%o A345551 from itertools import combinations_with_replacement as cwr
%o A345551 from collections import defaultdict
%o A345551 keep = defaultdict(lambda: 0)
%o A345551 power_terms = [x**3 for x in range(1, 1000)]
%o A345551 for pos in cwr(power_terms, 10):
%o A345551     tot = sum(pos)
%o A345551     keep[tot] += 1
%o A345551     rets = sorted([k for k, v in keep.items() if v >= 3])
%o A345551     for x in range(len(rets)):
%o A345551         print(rets[x])
%Y A345551 Cf. A345510, A345542, A345550, A345552, A345596, A345805.
%K A345551 nonn
%O A345551 1,1
%A A345551 _David Consiglio, Jr._, Jun 20 2021