cp's OEIS Frontend

A345719 Numbers that are the sum of six fifth powers in five or more ways.

%I A345719 #6 Jul 31 2021 16:37:35
%S A345719 54827300,74115800,74883600,75609125,113088250,120274275,166078869,
%T A345719 169692136,174781858,178736448,182341225,185558208,194939538,
%U A345719 203054589,218814275,235067008,250989825,251772882,252721458,255453233,258124975,274616694,282859667
%N A345719 Numbers that are the sum of six fifth powers in five or more ways.
%H A345719 Sean A. Irvine, <a href="/A345719/b345719.txt">Table of n, a(n) for n = 1..10000</a>
%e A345719 74115800 is a term because 74115800 = 1^5 + 4^5 + 21^5 + 21^5 + 29^5 + 34^5 = 1^5 + 8^5 + 14^5 + 23^5 + 32^5 + 32^5 = 4^5 + 11^5 + 13^5 + 22^5 + 24^5 + 36^5 = 5^5 + 6^5 + 19^5 + 20^5 + 24^5 + 36^5 = 6^5 + 25^5 + 25^5 + 25^5 + 29^5 + 30^5.
%o A345719 (Python)
%o A345719 from itertools import combinations_with_replacement as cwr
%o A345719 from collections import defaultdict
%o A345719 keep = defaultdict(lambda: 0)
%o A345719 power_terms = [x**5 for x in range(1, 1000)]
%o A345719 for pos in cwr(power_terms, 6):
%o A345719     tot = sum(pos)
%o A345719     keep[tot] += 1
%o A345719     rets = sorted([k for k, v in keep.items() if v >= 5])
%o A345719     for x in range(len(rets)):
%o A345719         print(rets[x])
%Y A345719 Cf. A345562, A345608, A345718, A345720, A345863, A346360.
%K A345719 nonn
%O A345719 1,1
%A A345719 _David Consiglio, Jr._, Jun 24 2021