cp's OEIS Frontend

A345853 Numbers that are the sum of ten fourth powers in exactly one ways.

%I A345853 #6 Jul 31 2021 20:00:03
%S A345853 10,25,40,55,70,85,90,100,105,115,120,130,135,145,150,160,165,170,180,
%T A345853 185,195,200,210,215,225,230,245,250,260,275,290,330,370,385,400,410,
%U A345853 435,450,465,490,500,515,530,570,610,625,634,640,649,650,664,675,679
%N A345853 Numbers that are the sum of ten fourth powers in exactly one ways.
%C A345853 Differs from A003344 at term 30 because 265 = 1^4 + 1^4 + 1^4 + 1^4 + 1^4 + 1^4 + 2^4 + 3^4 + 3^4 + 3^4 = 1^4 + 1^4 + 1^4 + 1^4 + 1^4 + 1^4 + 1^4 + 1^4 + 1^4 + 4^4.
%H A345853 Sean A. Irvine, <a href="/A345853/b345853.txt">Table of n, a(n) for n = 1..10000</a>
%e A345853 25 is a term because 25 = 1^4 + 1^4 + 1^4 + 1^4 + 1^4 + 1^4 + 1^4 + 1^4 + 1^4 + 2^4.
%o A345853 (Python)
%o A345853 from itertools import combinations_with_replacement as cwr
%o A345853 from collections import defaultdict
%o A345853 keep = defaultdict(lambda: 0)
%o A345853 power_terms = [x**4 for x in range(1, 1000)]
%o A345853 for pos in cwr(power_terms, 10):
%o A345853     tot = sum(pos)
%o A345853     keep[tot] += 1
%o A345853     rets = sorted([k for k, v in keep.items() if v == 1])
%o A345853     for x in range(len(rets)):
%o A345853         print(rets[x])
%Y A345853 Cf. A003344, A345803, A345843, A345854, A346346.
%K A345853 nonn
%O A345853 1,1
%A A345853 _David Consiglio, Jr._, Jun 26 2021