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A345862 Numbers that are the sum of ten fourth powers in exactly ten ways.

%I A345862 #6 Jul 31 2021 20:00:36
%S A345862 6885,7990,8035,8165,8275,8340,8515,8565,8580,9140,9235,9285,9445,
%T A345862 9495,9510,9540,9620,9670,9795,9830,9860,9924,9925,9990,10005,10164,
%U A345862 10294,10340,10374,10404,10420,10515,10534,10884,10950,10980,11075,11125,11190,11220
%N A345862 Numbers that are the sum of ten fourth powers in exactly ten ways.
%C A345862 Differs from A345603 at term 4 because 8100 = 1^4 + 1^4 + 1^4 + 2^4 + 2^4 + 2^4 + 4^4 + 6^4 + 7^4 + 8^4  = 1^4 + 1^4 + 1^4 + 2^4 + 2^4 + 3^4 + 6^4 + 6^4 + 6^4 + 8^4  = 1^4 + 1^4 + 1^4 + 4^4 + 4^4 + 4^4 + 4^4 + 4^4 + 4^4 + 9^4  = 1^4 + 1^4 + 1^4 + 4^4 + 4^4 + 6^4 + 6^4 + 6^4 + 6^4 + 7^4  = 1^4 + 2^4 + 2^4 + 2^4 + 2^4 + 2^4 + 3^4 + 3^4 + 6^4 + 9^4  = 2^4 + 2^4 + 2^4 + 2^4 + 3^4 + 3^4 + 3^4 + 6^4 + 7^4 + 8^4  = 2^4 + 2^4 + 2^4 + 3^4 + 4^4 + 4^4 + 4^4 + 7^4 + 7^4 + 7^4  = 2^4 + 2^4 + 3^4 + 3^4 + 4^4 + 4^4 + 6^4 + 6^4 + 7^4 + 7^4  = 2^4 + 3^4 + 3^4 + 3^4 + 4^4 + 4^4 + 4^4 + 4^4 + 4^4 + 9^4  = 2^4 + 3^4 + 3^4 + 3^4 + 4^4 + 6^4 + 6^4 + 6^4 + 6^4 + 7^4  = 3^4 + 3^4 + 3^4 + 3^4 + 6^4 + 6^4 + 6^4 + 6^4 + 6^4 + 6^4.
%H A345862 Sean A. Irvine, <a href="/A345862/b345862.txt">Table of n, a(n) for n = 1..10000</a>
%e A345862 7990 is a term because 7990 = 1^4 + 1^4 + 1^4 + 1^4 + 1^4 + 1^4 + 6^4 + 6^4 + 6^4 + 8^4 = 1^4 + 1^4 + 1^4 + 1^4 + 2^4 + 2^4 + 2^4 + 3^4 + 6^4 + 9^4 = 1^4 + 1^4 + 1^4 + 2^4 + 2^4 + 3^4 + 3^4 + 6^4 + 7^4 + 8^4 = 1^4 + 1^4 + 1^4 + 2^4 + 4^4 + 4^4 + 4^4 + 7^4 + 7^4 + 7^4 = 1^4 + 1^4 + 1^4 + 3^4 + 4^4 + 4^4 + 6^4 + 6^4 + 7^4 + 7^4 = 1^4 + 4^4 + 4^4 + 4^4 + 5^4 + 5^4 + 5^4 + 5^4 + 5^4 + 8^4 = 2^4 + 2^4 + 3^4 + 3^4 + 3^4 + 4^4 + 4^4 + 7^4 + 7^4 + 7^4 = 2^4 + 3^4 + 3^4 + 3^4 + 3^4 + 4^4 + 6^4 + 6^4 + 7^4 + 7^4 = 3^4 + 3^4 + 3^4 + 3^4 + 3^4 + 4^4 + 4^4 + 4^4 + 4^4 + 9^4 = 3^4 + 3^4 + 3^4 + 3^4 + 3^4 + 6^4 + 6^4 + 6^4 + 6^4 + 7^4.
%o A345862 (Python)
%o A345862 from itertools import combinations_with_replacement as cwr
%o A345862 from collections import defaultdict
%o A345862 keep = defaultdict(lambda: 0)
%o A345862 power_terms = [x**4 for x in range(1, 1000)]
%o A345862 for pos in cwr(power_terms, 10):
%o A345862     tot = sum(pos)
%o A345862     keep[tot] += 1
%o A345862     rets = sorted([k for k, v in keep.items() if v == 10])
%o A345862     for x in range(len(rets)):
%o A345862         print(rets[x])
%Y A345862 Cf. A345603, A345812, A345852, A345861, A346355.
%K A345862 nonn
%O A345862 1,1
%A A345862 _David Consiglio, Jr._, Jun 26 2021