cp's OEIS Frontend

A346259 Numbers that are the sum of seven fifth powers in exactly ten ways.

%I A346259 #7 Jul 31 2021 19:11:40
%S A346259 134581976,189642309,219063107,235438301,252277376,275782407,
%T A346259 300919884,308188849,309631268,315635200,327287951,335530174,
%U A346259 342030094,358852218,379913293,384699424,387538625,391133568,395423876,405307926,421322507,423673757,425588250
%N A346259 Numbers that are the sum of seven fifth powers in exactly ten ways.
%C A346259 Differs from A345643 at term 7 because 281935070 = 17^5 + 17^5 + 18^5 + 21^5 + 23^5 + 26^5 + 48^5 = 7^5 + 17^5 + 20^5 + 23^5 + 24^5 + 32^5 + 47^5 = 7^5 + 13^5 + 13^5 + 26^5 + 30^5 + 36^5 + 45^5 = 1^5 + 13^5 + 21^5 + 21^5 + 33^5 + 37^5 + 44^5 = 6^5 + 7^5 + 13^5 + 31^5 + 34^5 + 36^5 + 43^5 = 4^5 + 8^5 + 16^5 + 29^5 + 31^5 + 41^5 + 41^5 = 6^5 + 8^5 + 12^5 + 28^5 + 37^5 + 38^5 + 41^5 = 3^5 + 6^5 + 15^5 + 32^5 + 35^5 + 38^5 + 41^5 = 7^5 + 24^5 + 25^5 + 32^5 + 34^5 + 37^5 + 41^5 = 13^5 + 20^5 + 21^5 + 34^5 + 35^5 + 36^5 + 41^5 = 8^5 + 24^5 + 26^5 + 31^5 + 31^5 + 40^5 + 40^5.
%H A346259 Sean A. Irvine, <a href="/A346259/b346259.txt">Table of n, a(n) for n = 1..4377</a>
%e A346259 134581976 is a term because 134581976 = 1^5 + 14^5 + 17^5 + 18^5 + 26^5 + 31^5 + 39^5 = 1^5 + 1^5 + 10^5 + 12^5 + 19^5 + 35^5 + 38^5 = 8^5 + 11^5 + 12^5 + 17^5 + 27^5 + 33^5 + 38^5 = 3^5 + 12^5 + 12^5 + 21^5 + 28^5 + 32^5 + 38^5 = 4^5 + 11^5 + 13^5 + 22^5 + 24^5 + 36^5 + 36^5 = 5^5 + 6^5 + 19^5 + 20^5 + 24^5 + 36^5 + 36^5 = 1^5 + 4^5 + 21^5 + 21^5 + 29^5 + 34^5 + 36^5 = 1^5 + 8^5 + 14^5 + 23^5 + 32^5 + 32^5 + 36^5 = 6^5 + 25^5 + 25^5 + 25^5 + 29^5 + 30^5 + 36^5 = 12^5 + 20^5 + 21^5 + 26^5 + 28^5 + 34^5 + 35^5.
%o A346259 (Python)
%o A346259 from itertools import combinations_with_replacement as cwr
%o A346259 from collections import defaultdict
%o A346259 keep = defaultdict(lambda: 0)
%o A346259 power_terms = [x**5 for x in range(1, 1000)]
%o A346259 for pos in cwr(power_terms, 7):
%o A346259     tot = sum(pos)
%o A346259     keep[tot] += 1
%o A346259     rets = sorted([k for k, v in keep.items() if v == 10])
%o A346259     for x in range(len(rets)):
%o A346259         print(rets[x])
%Y A346259 Cf. A345643, A345832, A346286, A346335, A346365.
%K A346259 nonn
%O A346259 1,1
%A A346259 _David Consiglio, Jr._, Jul 12 2021