cp's OEIS Frontend

A346808 Numbers that are the sum of ten squares in ten or more ways.

%I A346808 #10 May 10 2024 02:17:58
%S A346808 61,64,66,67,69,70,72,73,74,75,76,77,78,79,80,81,82,83,84,85,86,87,88,
%T A346808 89,90,91,92,93,94,95,96,97,98,99,100,101,102,103,104,105,106,107,108,
%U A346808 109,110,111,112,113,114,115,116,117,118,119,120,121,122,123,124
%N A346808 Numbers that are the sum of ten squares in ten or more ways.
%H A346808 Sean A. Irvine, <a href="/A346808/b346808.txt">Table of n, a(n) for n = 1..10000</a>
%e A346808 64 = 1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 2^2 + 2^2 + 7^2
%e A346808    = 1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 2^2 + 3^2 + 3^2 + 6^2
%e A346808    = 1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 2^2 + 2^2 + 5^2 + 5^2
%e A346808    = 1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 4^2 + 4^2 + 5^2
%e A346808    = 1^2 + 1^2 + 1^2 + 2^2 + 2^2 + 2^2 + 2^2 + 2^2 + 4^2 + 5^2
%e A346808    = 1^2 + 1^2 + 1^2 + 1^2 + 2^2 + 2^2 + 3^2 + 3^2 + 3^2 + 5^2
%e A346808    = 1^2 + 1^2 + 1^2 + 1^2 + 2^2 + 2^2 + 2^2 + 4^2 + 4^2 + 4^2
%e A346808    = 1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 3^2 + 3^2 + 3^2 + 4^2 + 4^2
%e A346808    = 2^2 + 2^2 + 2^2 + 2^2 + 2^2 + 2^2 + 2^2 + 2^2 + 4^2 + 4^2
%e A346808    = 1^2 + 2^2 + 2^2 + 2^2 + 2^2 + 2^2 + 3^2 + 3^2 + 3^2 + 4^2
%e A346808    = 1^2 + 1^2 + 2^2 + 2^2 + 3^2 + 3^2 + 3^2 + 3^2 + 3^2 + 3^2
%e A346808 so 64 is a term.
%o A346808 (Python)
%o A346808 from itertools import combinations_with_replacement as cwr
%o A346808 from collections import defaultdict
%o A346808 keep = defaultdict(lambda: 0)
%o A346808 power_terms = [x**2 for x in range(1, 1000)]
%o A346808 for pos in cwr(power_terms, 10):
%o A346808     tot = sum(pos)
%o A346808     keep[tot] += 1
%o A346808     rets = sorted([k for k, v in keep.items() if v >= 10])
%o A346808     for x in range(len(rets)):
%o A346808         print(rets[x])
%Y A346808 Cf. A345558, A346803. Subsequence of A346807.
%K A346808 nonn
%O A346808 1,1
%A A346808 _David Consiglio, Jr._, Aug 04 2021