cp's OEIS Frontend

A347758 Let s(k) be the finite permutation associated to A109299(k); s(a(n)) is the inverse of s(n).

%I A347758 #17 Sep 18 2021 10:13:50
%S A347758 1,2,3,4,5,7,6,8,9,10,11,13,12,14,15,19,18,17,16,21,20,23,22,24,25,28,
%T A347758 29,26,27,30,31,32,33,34,35,39,38,37,36,42,41,40,46,44,48,43,47,45,53,
%U A347758 54,55,52,49,50,51,58,61,56,60,59,57,63,62,65,64,66,68
%N A347758 Let s(k) be the finite permutation associated to A109299(k); s(a(n)) is the inverse of s(n).
%C A347758 This sequence is a self-inverse permutation of the positive integers.
%H A347758 Rémy Sigrist, <a href="/A347758/b347758.txt">Table of n, a(n) for n = 1..10000</a>
%H A347758 Rémy Sigrist, <a href="/A347758/a347758.gp.txt">PARI program for A347758</a>
%H A347758 <a href="/index/Per#IntegerPermutation">Index entries for sequences that are permutations of the natural numbers</a>
%e A347758 For n = 42:
%e A347758 - A109299(42) = 2^5 * 3^3 * 5^4 * 7^1 * 11^2,
%e A347758 - so s(42) = [5, 3, 4, 1, 2],
%e A347758 - and s(a(42)) = [4, 5, 2, 3, 1],
%e A347758 - and A347752(a(42)) = 2^4 * 3^5 * 5^2 * 7^3 * 11^1 = A109299(40),
%e A347758 - hence a(42) = 40.
%o A347758 (PARI) See Links section.
%Y A347758 Cf. A109299, A347759.
%K A347758 nonn,look
%O A347758 1,2
%A A347758 _Rémy Sigrist_, Sep 12 2021