A347791 Inventory sequence using prime divisors (with multiplicity): Record the number of terms thus far which are divisible by every prime, then the number of terms thus far not divisible by any prime, then the number divisible (once) by a single prime, then 2 (including with multiplicity), then 3 etc until a zero is recorded. Repeat after every zero term.
0, 1, 1, 0, 2, 2, 2, 0, 3, 2, 5, 0, 4, 2, 7, 1, 0, 5, 3, 10, 2, 0, 6, 3, 12, 3, 1, 0, 7, 4, 14, 5, 1, 0, 8, 5, 16, 5, 2, 1, 0, 9, 6, 18, 7, 3, 1, 0, 10, 7, 21, 9, 3, 1, 0, 11, 8, 23, 10, 4, 1, 0, 12, 9, 24, 13, 5, 2, 0, 13, 9, 28, 14, 6, 2, 0, 14, 9, 29, 18, 7
Offset: 0
Examples
a(0)=0 because at this point there are zero terms divisible by every prime. a(1)=1 because there is now one term (0) which is divisible by every prime. a(2)=1 because there is now one term (1) with no prime divisor. a(3)=0 because at this point there is no term divisible by one prime, and so on. As an irregular triangle the sequence begins: 0; 1, 1, 0; 2, 2, 2, 0; 3, 2, 5, 0; 4, 2, 7, 1, 0; 5, 3, 10, 2, 0; 6, 3, 12, 3, 1, 0; 7, 4, 14, 5, 1, 0; 8, 5, 16, 5, 2, 1, 0; 9, 6, 18, 7, 3, 1, 0; 10, 7, 21, 9, 3, 1, 0; 11, 8, 23, 10, 4, 1, 0; etc.
Links
- Michael De Vlieger, Table of n, a(n) for n = 0..10000 (rows 0 <= n <= 836, flattened)
- Michael De Vlieger, Log-log scatterplot of row n for 1 <= n <= 2^16 (1199674 terms), with color function showing k, black represents the number of 0s, red 1s, orange primes, etc.
Programs
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Mathematica
Block[{a = {}, c, k, m}, c[-1] = 0; Do[k = -1; c[-1]++; AppendTo[a, 0]; While[IntegerQ[c[k]], AppendTo[a, c[k]]; Set[m, PrimeOmega[c[k]]]; If[IntegerQ[c[m]], c[m]++, Set[c[m], 1]]; k++], 10]; a] (* Michael De Vlieger, Sep 15 2021 *)
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