cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A347791 Inventory sequence using prime divisors (with multiplicity): Record the number of terms thus far which are divisible by every prime, then the number of terms thus far not divisible by any prime, then the number divisible (once) by a single prime, then 2 (including with multiplicity), then 3 etc until a zero is recorded. Repeat after every zero term.

Original entry on oeis.org

0, 1, 1, 0, 2, 2, 2, 0, 3, 2, 5, 0, 4, 2, 7, 1, 0, 5, 3, 10, 2, 0, 6, 3, 12, 3, 1, 0, 7, 4, 14, 5, 1, 0, 8, 5, 16, 5, 2, 1, 0, 9, 6, 18, 7, 3, 1, 0, 10, 7, 21, 9, 3, 1, 0, 11, 8, 23, 10, 4, 1, 0, 12, 9, 24, 13, 5, 2, 0, 13, 9, 28, 14, 6, 2, 0, 14, 9, 29, 18, 7
Offset: 0

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Author

David James Sycamore, Sep 13 2021

Keywords

Comments

Inspired by the original Inventory sequence (A342585). It follows from the definition that zero appears infinitely many times. Every nonzero number number appears because the number of zero terms increments at every extension of the sequence between consecutive zeros. Since the count for each number of divisors increments (eventually) as the sequence extends, it follows that every number appears infinitely many times.
The count of terms divisible by every prime is the number of zeros, the count of terms divisible by no prime is the number of 1s, the count of terms divisible by one prime (once) is the number of primes, etc.

Examples

			a(0)=0 because at this point there are zero terms divisible by every prime. a(1)=1 because there is now one term (0) which is divisible by every prime. a(2)=1 because there is now one term (1) with no prime divisor. a(3)=0 because at this point there is no term divisible by one prime, and so on.
As an irregular triangle the sequence begins:
   0;
   1,  1,  0;
   2,  2,  2,  0;
   3,  2,  5,  0;
   4,  2,  7,  1,  0;
   5,  3, 10,  2,  0;
   6,  3, 12,  3,  1,  0;
   7,  4, 14,  5,  1,  0;
   8,  5, 16,  5,  2,  1,  0;
   9,  6, 18,  7,  3,  1,  0;
  10,  7, 21,  9,  3,  1,  0;
  11,  8, 23, 10,  4,  1,  0; etc.
		

Crossrefs

Programs

  • Mathematica
    Block[{a = {}, c, k, m}, c[-1] = 0; Do[k = -1; c[-1]++; AppendTo[a, 0]; While[IntegerQ[c[k]], AppendTo[a, c[k]]; Set[m, PrimeOmega[c[k]]]; If[IntegerQ[c[m]], c[m]++, Set[c[m], 1]]; k++], 10]; a] (* Michael De Vlieger, Sep 15 2021 *)