A349991 For any n >= 0, consider a sandpile model on the infinite hexagonal lattice starting with n grains at the origin, the other sites being empty; a(n) gives the number of nonempty sites after stabilization of this sandpile model.
0, 1, 1, 1, 1, 1, 6, 7, 7, 7, 7, 7, 6, 7, 7, 7, 7, 7, 6, 7, 7, 7, 7, 7, 6, 7, 7, 7, 7, 7, 6, 7, 7, 7, 7, 7, 18, 19, 19, 19, 19, 19, 18, 19, 19, 19, 19, 19, 18, 19, 19, 19, 19, 19, 18, 19, 19, 19, 19, 19, 18, 19, 19, 19, 19, 19, 18, 19, 19, 19, 19, 19, 24, 25
Offset: 0
Keywords
Examples
For n = 54: - after stabilization, we have the following configuration: 2 4 4 2 3 2 3 3 4 4 3 3 2 3 2 4 4 2 - we have 18 nonnempty sites, - so a(54) = 18.
Links
- Rémy Sigrist, Colored representation of the stabilized configuration for n = 1000000 (white, green, purple, gold, blue and red pixels correspond to sites with 0, 1, 2, 3, 4 and 5 grains, respectively)
- Rémy Sigrist, C++ program for A349991
- Wikipedia, Sandpile models on infinite grids
Crossrefs
Cf. A349990.
Formula
a(6*n) + 1 = a(6*n + k) for k = 1..5.
Comments