A350979 a(0)=1, a(1)=652, thereafter a(n) = 254*a(n-1)-a(n-2)+378.
1, 652, 165985, 42159916, 10708453057, 2719904916940, 690845140450081, 175471945769404012, 44569183380288169345, 11320397106647425609996, 2875336295905065816770017, 730324098762780070033974700, 185499445749450232722812804161, 47116128896261596331524418282572, 11967311240204696017974479430969505
Offset: 0
Keywords
References
- P.-F. Teilhet, Query 2228, L'Intermédiaire des Mathématiciens, 11 (1904), 44-45.
Links
- Index entries for linear recurrences with constant coefficients, signature (255,-255,1).
Formula
From Chai Wah Wu, Mar 07 2022: (Start)
a(n) = 255*a(n-1) - 255*a(n-2) + a(n-3) for n > 3.
G.f.: x*(20*x^2 - 397*x - 1)/((x - 1)*(x^2 - 254*x + 1)). (End)
Comments