A351102 Variation of the Sisyphus sequence A350877: the same rules apply except that each time a(n) is divided by a prime the dividing prime is incremented to the next prime.
1, 3, 6, 3, 8, 15, 5, 16, 29, 46, 65, 13, 36, 65, 96, 133, 19, 60, 103, 150, 203, 262, 323, 390, 461, 534, 613, 696, 785, 882, 983, 1086, 1193, 1302, 1415, 1542, 1673, 1810, 1949, 2098, 2249, 2406, 2569, 2736, 2909, 3088, 3269, 3460, 3653, 3850, 350, 549, 760, 983, 1210, 1439, 1672
Offset: 1
Keywords
Examples
a(3) = 6 as a(2) = 3, which is not divisible by the current dividing prime 2, and the next additive prime is 3, so a(3) = 3 + 3 = 6. a(4) = 3 as a(3) = 6, the current dividing prime is 2, and 6/2 = 3. As 3 is not divisible by 2, the divisions by 2 stop, and the dividing prime now becomes 3. a(5) = 8 as a(4) = 3 and the next additive prime is 5, so a(5) = 3 + 5 = 8. a(6) = 15 as a(5) = 8, which is not divisible by 3, and the next additive prime is 7, so a(6) = 8 + 7 = 15. a(7) = 5 as a(6) = 15, the current dividing prime is 3, and 15/3 = 5. As 5 is not divisible by 3, the divisions by 3 stop, and the dividing prime now becomes 5. a(8) = 16 as a(7) = 5 and the next additive prime is 11, so a(8) = 5 + 11 = 16. a(446) = 22090, a(447) = 470, a(448) = 10. This is the first time that the current term and the resulting quotient are both divisible by the current dividing prime, 47 in this case. The current additive prime is 3011, so a(449) = 3021. Coincidently 3021 is divisible by the next dividing prime 51, so a(450) = 57. This is the shortest possible gap between divisions by different primes.
Links
- Scott R. Shannon, Image of the first 100000 terms.
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