A352549 Irregular table, read by rows: row n lists all numbers equal to n times the number of their divisors.
1, 2, 8, 12, 9, 18, 24, 36, 40, 60, 72, 56, 84, 80, 96, 108, 180, 88, 132, 240, 104, 156, 252, 360, 128, 288, 136, 204, 152, 228, 480, 504, 396, 184, 276, 384, 720, 225, 450, 600, 468, 560, 672, 232, 348, 248, 372, 448, 792, 612, 1260, 864, 296, 444, 684
Offset: 1
Examples
The table starts: row n | numbers j such that j = n*A000005(j) 1 | 1, 2 2 | 8, 12 3 | 9, 18, 24 4 | 36 5 | 40, 60 6 | 72 7 | 56, 84 ... If j = p1^e1 * p2^e2 * ... * pK^eK, let d = A000005(j) = (e1+1)*...*(eK+1) for the number of divisors of j (or d(m) for the number of divisors of m). j = 1 with d = 1 and j = 2 with d = 2 are the only numbers with j/d = 1, listed in row 1. j = 8 = 2^3 with d = 4 and j = 12 = 2^2*3 with d = 3*2 = 6 are the only numbers with j/d = 2, listed in row 2. Indeed, let j = 2^k*m with odd m, then d = (k+1)*d(m), and j/d = 2 <=> 2^(k-1)*m = (k+1)*d(m), k >= 1. For k = 1, m = 2*d(m), no solution with odd m. For k = 2, 2*m = 3*d(m), the only solution is m = 3, d(m) = 2, j = 12. For k = 3, 4*m = 4*d(m), m = 2 is the only solution. For k > 3, there is no solution: (k+1) will be smaller than 2^(k-1), and for d(m) to have enough powers of 2, m must have 3 (or larger primes) raised to odd powers, but one easily sees that then the l.h.s. is always larger than the r.h.s. j = 9 = 3^2 with d = 3, j = 18 = 2*3^2 with d = 2*3 = 6, and j = 24 = 2^3*3 with d = 4*2 = 8 are the only numbers with j/d = 3, listed in row 3. j = 36 = 2^2*3^2 with d = 3*3 is the only number with j/d = 4, listed in row 4. 18 = A036763(1) is the smallest positive integer not of the form j/d(j) for any n, therefore row 18 is empty.
Crossrefs
Programs
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PARI
vecsort(A033950_upto(1300), n->n/numdiv(n))[1..55]
Comments