A353241 a(0) = 1; for n > 0, a(n) = binary length of (A109812(n) + A109812(n+1)).
1, 2, 3, 3, 4, 4, 4, 5, 5, 4, 5, 5, 5, 5, 6, 6, 5, 6, 6, 5, 6, 6, 6, 6, 6, 6, 6, 6, 7, 7, 6, 7, 7, 6, 7, 7, 6, 7, 7, 7, 7, 7, 7, 6, 7, 7, 7, 7, 7, 8, 8, 7, 8, 8, 7, 8, 8, 7, 8, 8, 7, 7, 7, 7, 7, 7, 7, 7, 7, 8, 8, 7, 8, 8, 8, 8, 8, 8, 8, 8, 7, 8, 8, 8, 8, 7, 8
Offset: 0
Examples
For n = 7: - A109812(7) + A109812(8) = 10 + 16 = 26, - 26 in binary is "11010", - so a(7) = 5
Links
- N. J. A. Sloane, Table of n, a(n) for n = 0..20000 (first 10000 terms from Rémy Sigrist)
- Rémy Sigrist, C++ program
Comments