A353342 Numbers k such that k and k^3 use only even digits.
0, 2, 4, 20, 40, 200, 202, 400, 2000, 2002, 2020, 4000, 20000, 20002, 20020, 20200, 40000, 200000, 200002, 200020, 200200, 202000, 400000, 2000000, 2000002, 2000020, 2000200, 2002000, 2020000, 4000000, 20000000, 20000002, 20000020, 20000200, 20000202, 20002000, 20002002, 20020000, 20200000
Offset: 1
Programs
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Mathematica
seq[ndigmax_] := Module[{nums = Tuples[{0, 2, 4, 6, 8}, ndigmax]}, Select[FromDigits /@ nums, AllTrue[IntegerDigits[#^3], EvenQ] &]]; seq[8] (* Amiram Eldar, May 06 2022 *)
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Python
from itertools import count, islice, product def agen(): # generator of terms for digits in count(1): for p in product("02468", repeat=digits): if len(p) > 1 and p[0] == "0": continue k = int("".join(p)) if set(str(k**3)) <= set("02468"): yield k print(list(islice(agen(), 40))) # Michael S. Branicky, May 06 2022
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