A353542 a(n) is the least start of a run of n consecutive numbers whose abundancy index is larger than Pi^2/6.

4, 44, 188, 8110374, 330921744

Offset: 1

Author

Amiram Eldar, Apr 25 2022

Keywords

• nonn
• more

Comments

By the Chinese Remainder Theorem, a(n) exists for all n. The proof is similar to the proof that is given for A094268.

Examples

			a(1) = 4 since 4 is the least term of A353537.
a(2) = 44 since 44 is the least term of A353538.
		

Crossrefs

Cf. A000203, A013661, A094268.

Cf. A353537, A353538, A353539, A353540, A353541.